a (m/s2 4 2- 0+ 0 t (s) 4 2

A particle moves along the x-axis. Its coordinate in meters is given by x(t) = 12t – 3.0t2, where the time is in seconds. The particle is momentarily at rest at t = O 2.0 s O 3.0 s O 4.0 s 5.0 s

At t = 10 s, a particle is moving from left to right with a speed of 5.0 m/s. At t = 20 s, the particle is moving right to left with a speed of 8.0 m/s. Assuming the particle's acceleration is constant, determine its acceleration

The position of an object as a function of time is given as x = At3 + Bt2 + Ct + D . The constants are A = 2.41 m/s3 B = 1.37 m/s2 ' , C = -4.61 m/s, and D = 3.35 m. What is the velocity of the object at t = 19.10 s? m/s

A particle moves along the x-axis according to the equation x 2.00 + 3.00t - the acceleration of the particle. 1.00t2. where x is in meters and t is in seconds. At t=D3.00s, find

a particle moves in one dimension, and its position as a function of time is given by x = (1.9m/s)t + (-2.6 m/s^2)t^2  what is the particles average velocity from t = 0.45 s to t = 0.55 s?    what is the particles average velocity from t = 0.49 s to t = 0.51 s?

The position of an object as it moves along the x axis is given by x= 10e ^-5t m where t is in s. What is the velocity and acceleration of the particle at t=1.0s

the acceleration a versus time t for a particle moving along an x axis. the a-axis scale is set by as = 12 m/s2. at t = -2.0 s, the particles velocity is 7.0 m/s. what is its velocity at t = 6 s?