A particle moves along the +ve direction of x-axis. Its position x depends on time t as x=at3+bt2+c+d. Let dx/dt represent instantaneous velocity d2x/dt2 represents instantaneous acceleration (α) of the particle.The average acc. of the particle is defined as <α> =∫αdt/dt. Find the average acc. in time interval t=0 to t=1s.

A particle moves along the x-axis. The velocity of this particle as a function of time is shown in the figure. Assume the particle is located at x = 0 m at time t = 0 s. What is the acceleration of the particle at time t = 22.0 s? What is the position of the particle along the x-axis at time t = 22.0 s? What is the net displacement of the particle between time t = 4.0 s and t = 36.0 s?

The position of an object as a function of time is given as x = At3 + Bt2 + Ct + D . The constants are A = 2.41 m/s3 B = 1.37 m/s2 ' , C = -4.61 m/s, and D = 3.35 m. What is the velocity of the object at t = 19.10 s? m/s

Hello. I am working on a problem with motion. The questions asks me to calculate the maximum height (h1),  total time (t2), and speed of a ball right before it hits the ground. The question states that A person is throwing a ball upward into the air with an initial speed Vo = 10m/s. Assume that the instant when the ball is released, the person's hand is at a height ho = 1.5m. The speed of the ball at its peak height is zero, and the question needs to be solved in ascending part and descending part. I don't understand how to solve for the maximum height. What is the correct formula to use and why? For other questions like this, I will be able to solve them if I know the formulas for the ascending of the ball and the descent of the ball as well as the explanation. Thank you. For the sake of the question, the ball is being thrown straight up.