College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An automobile weighing 1.19 x 104 N has weight equally distributed over its wheels. The weight of the car causes each tire to be slightly flattened on the bottom so that there is a surface area in contact with the road. The gauge pressure of the air in the tire is 1.90 x 105 Pa (27.55 lb/in2). Find the area of contact, assuming that the only forces on the section of tire in contact with the road are the air pressure and the normal force exerted by the surface of the road.arrow_forwardSuppose you measure a standing person’s blood pressure by placing the cuff on his leg 0.495 m below the heart. For this problem, assume that there is no loss of pressure due to resistance in the circulatory system (a reasonable assumption, since major arteries are large). The density of blood is 1.05 × 103 kg/m3. Calculate the systolic pressure you would observe, in units of mm Hg, if the pressure at the heart was 120 over 80 mm Hg. Note that the to (and greater) number is systolic pressure. Ps? Calculate the diastolic pressure you would observe, in unites of mm Hg, if the pressure at heart was 120 overc80cmm Hg. Note that the bottom (smaller) number is the diastolic pressure.Pd?arrow_forwardSuppose you measure a standing person’s blood pressure by placing the cuff on his leg 0.525 m below the heart. For this problem, assume that there is no loss of pressure due to resistance in the circulatory system (a reasonable assumption, since major arteries are large). The density of blood is 1.05×103 kg/m3 a. Calculate the systolic pressure you would observe, in units of mm Hgmm Hg, if the pressure at the heart was 120 over 80 mm Hg. Note that the top (and greater) number is the systolic pressure. b. Calculate the diastolic pressure you would observe, in units of mm Hgmm Hg, if the pressure at the heart was 120 over 80 mm Hg. Note that the bottom (smaller) number is the diastolic pressure.arrow_forward
- Question 1 a) Consider the forces acting on an infinitesimal fluid element located at radius r inside a star, where the star is in hydrostatic equilibrium. Show that the buoyancy force acting on the fluid element may be written as Pe dv dt = -(Pe - p)g where Pe is the density inside the fluid element, p is the density of the gas in the surrounding gas at radius r, v is the velocity of the fluid element and g is local acceleration due to gravity. For full marks you should explain each step of your derivation. b) With the aid of a diagram, explain the condition required for convection to occur by considering the small displacement of a fluid element from its original equilibrium location within a star.arrow_forwardAt 20°C, the viscosity of water is 1.0x10-3 Pa-s and the viscosity of molasses is 51 Pa-s. Consider two tubes of the same length L, with fixed pressure difference Ap across each pipe. If water flows through Pipe 1 and molasses flows through Pipe 2, and both have the same flow rate Q, what is the ratio of the radius of Pipe 2 to Pipe 1?arrow_forwardWhen a person inhales, air moves down the bronchus (windpipe) at 13.8 cm/s. The average flow speed of the air doubles through a constriction in the bronchus. Assuming incompressible flow, determine the pressure drop in the constriction. Neglect the change of pressure due to change in height ?y in the wind pipe. If the pressure goes down then the pressure drop is negative. Use 1.20 kg/m33 for the density of air.arrow_forward
- The height of mercury in a barometer is measured at 85.0 cm. Compute for the atmospheric pressure.arrow_forwardProblem 1: A certain rigid aluminum container contains a liquid at a gauge pressure of P0 = 2.02 × 105 Pa at sea level where the atmospheric pressure is Pa = 1.01 × 105 Pa. The volume of the container is V0 = 2.15 × 10-4 m3. The maximum difference between the pressure inside and outside that this particular container can withstand before bursting or imploding is ΔPmax = 2.41 × 105 Pa.For this problem, assume that the density of air maintains a constant value of ρa = 1.20 kg / m3 and that the density of seawater maintains a constant value of ρs = 1025 kg / m3. What is the maximum depth dmax in meters below the surface of the ocean that the container can be taken before imploding?arrow_forwardYou are with an excursion party on an exploration of the surface of Mars. You find a small lake of water of that 1.76 m. Assume the density of the freshwater is unchanged on Mars. You measure the absolute pressure at the bottom of the lake to be one 161,800 Pa. What is the absolute pressure (in atm) at the surface of the lake. Assume the value of G on Mars is 3.72 m/s^2arrow_forward
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