Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Given:

mh = Mass of Hot water = 50.0 g

mc= Mass of Cold water = 50.0 g

Temperature of Hot water = Th = 48.4 °C

Temperature of Cold water = Tc = 23.8 °C

Result temperature = T = 35.7 °C

Specific Heat capacity of water = Cw= 4.184 J/g°C

Heat capacity of calorimeter = C

Heat absorbed by cold water + heat absorbed by calorimeter = Heat released by hot water

[mc * Cw * (T − Tc)]+ [C(T − Tc)] =− [mh * Cw * ( T − Th )]

---> [50 g  * 4.184 J/g°C* (35.7 − 23.8)°C]+ [C(35.7 − 23.8)°C] =− [50 g  * 4.184 J/g°C* ( 35.7 − 48.4)°C]2489.48 + 11.9C =2656.84C = 14.06 J/°C

^Use this data given above and the table of Time and Temperature to answer the question (including parts a, b, and c).

2. The following is temperature data recorded for reaction 2 and rounded off to the nearest 0.1 °C.
Time (min)
Temperature (*C)
1
25.4
2
25.4
25.3
25.3
3
4
25.3
added 1.98 g of NaOH(s)
34.5
7
8.
34.3
9
34.1
10
33.9
11
33.7
12
33.5
13
33.3
(a) Make a graph of this data. Be sure to make a high quality, easy-to-plot, easy-to-read graph. Attach
the graph to this prelab assignment.
(b) Línearly extrapolate to the time of mixing and determine AT.
(c) Calculate qr and AH, for the reaction. Give energy units in kilojoules. Assume 52.0 g of selution
are present and that the heat capacity the calorimeter, Ccal, is that calculated in question 1 above,
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Transcribed Image Text:2. The following is temperature data recorded for reaction 2 and rounded off to the nearest 0.1 °C. Time (min) Temperature (*C) 1 25.4 2 25.4 25.3 25.3 3 4 25.3 added 1.98 g of NaOH(s) 34.5 7 8. 34.3 9 34.1 10 33.9 11 33.7 12 33.5 13 33.3 (a) Make a graph of this data. Be sure to make a high quality, easy-to-plot, easy-to-read graph. Attach the graph to this prelab assignment. (b) Línearly extrapolate to the time of mixing and determine AT. (c) Calculate qr and AH, for the reaction. Give energy units in kilojoules. Assume 52.0 g of selution are present and that the heat capacity the calorimeter, Ccal, is that calculated in question 1 above,
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