A long, nonconducting, solid cylinder of radius 5.3 cm has a nonuniform volume charge density p that is a function of radial distancer from the cylinder axis:p- Ar. For A- 3.5 uC/m, what is the magnitude of the electric field at (a) r 1.5 cm and (b) r11 cm.
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- 1 ! 7 A skát с A spherically symmetric charge distribution produces the electric field E=( 5400 r²) N/C, where r is in m. Z mylabmastering.pearson.com/?courseld=12649908&key=55673220682936520262024#/ 2 pos W S X 3 20 F3 E D $ 4 C 888 R F What is the electric field strength at r= 16.0 cm ? Express your answer in newtons per coulomb. VG ΑΣΦ 4 Submit Part B Submit Part C What is the electric flux through a 32.0-cm-diameter spherical surface that is concentric with the charge distribution? Express your answer in newton meters squared per coulomb. ΕΠΙ ΑΣΦ % [VG| ΑΣΦ 5 Request Answer V FO Request Answer T How much charge is inside this 32.0-cm-diameter spherical surface? Express your answer in coulombs. G 4 a ^ 6 C 244 MacBook Air Y B SMC & ? 7 H ? N/C 80 F7 N-m²/C U C N H 8 - DII FS 1 ( 9 M DD K chegg.com X C ☆ O O MOSISO O 4 PAn infinite cylinder of radius R has a charge density given by p(r) = ar³, where r is the perpendicular distance from the axis of the cylinder, and a is a constant. Show that the electric field for r > R given by aRT E(r) : 7€or is the same as that obtained if all the charge is concentrated in an infinitely thin wire.E(r) = Bzi - ax'y'j+ (6@yxy + Bóz³) k %3D where a, B, y and & are constants and r = xi+yj+zk. Find the corresponding charge density p(r).
- A non-uniformiy charged insulating sphere has a volume charge density p that is expressed as p= Br where Bis a constant, and ris the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. so, we have p = dal - B So we can write this as dg = B dV But, dV = dr By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B =A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. so, we have P = dq/ = B so we can write this as dq = B dV But, dV = dr By substitution, we get the following dq = 4B dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B = 4)A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. so, we have p = dq/ So we can write this as dq = B dV %3D But, dV = dr
- A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. So, we haye p = dq/ So we can write this as dq = B dV But, dV = dr By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = BT Rearranging, we get B = /( TA non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, andris the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as p= where in is the infinitesimal charge and is the infinitesimal volume. So, we have p = dq/ = B So we can write this as dq = B dv But, dV = TT dr By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B = 4)A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where Bis a constant, and ris the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as where in is the infinitesimal charge and is the infinitesimal volume. so, we have p = dq/ - BA So we can write this as dq = dv But. dV = dr By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B =
- The charge density of a non-uniformly charged sphere of radius 1.0 m is given as: For rs 1.0 m; p(r)= Po(1-4r/3) For r> 1.0 m; p(r)= 0, where r is in meters. What is the value of r in meters for which the electric field is maximum?A non-uniformly charged insulating sphere has a volume charge density p that is expressed as p= Br where B is a constant, and r is the radius from the center of the sphere. If the, the total charge of the sphere is Q and its maximum radius is R. What is the value for B? Sol. By definition, the volume charge density is expressed infinitesimally as where in is the infinitesimal charge and is the infinitesimal volume. so, we have p = dq/ so we can write this as dq = B dV But, dV = dr By substitution, we get the following dq = 4BT dr Using Integration operation and evaluating its limits, the equation, leads to Q = Rearranging, we get B = 4)An infinitely long conducting cylinder of radius 2 cm has a linear charge density +4 µC/m is surrounded by an insulating shell of inner radius 8 cm and outer radius 12 cm. The insulating shell has a net linear charge density of +3 µC/m (Figure 1) Figure 1 of 1 Insulating Cylindrical Shell Central Cylinder Acyl Ashell