A large planet with a mass of 3.4e25 kg has a moon with a mass of 1.5e23 kg. If the moon orbits the a planet at a radius of 4. 1e8 km, what is the magnitude of the gravitational force between the planet and the moon?

Assume the earth's mass is 80.004 x 1025 kg, and radius is 35.532 x 103 miles, what would be the gravitational acceleration on such an planet in unit of m/s2? Use G=6.67x 10 -11 Nm2/kg2.

Gravitational force is F = Gm1m2/r². Set G = 1 and m1 = 1, where m2 will be a planet with 1800 times Earth's mass (so m2 = 1800) and 30 times Earth's radius (so r = 30). What will F be?

A landing craft with mass M is in a circular orbit a distance d above the surface of a planet. The period ofthe orbit is T. The astronauts in the landing craft measure the diameter of the planet to be D. The landing craft sets down at the north pole of the planet. a)What is the weight of a person of mass m as they step out onto the plant’s surface? b)Suppose days on this planet last t seconds (i.e. the planet rotates about its axis once every t seconds).Write an expression for the astronaut’s perceived weight at the equator in terms of their weight at the north pole. (Hint: think about centripetal force)

The radius and mass of a planet are 5.39E+06_m and 2.56E+25_kg, respectively. A spaceship is in orbit at a distance of 1680_km above the surface of the planet. Find the orbital speed of the ship. 4. 12990_m/s 15540_m/s F. А. 13670 _m/s D. В. 14650_m/s E. C. 14180_m/s 12170_m/s

Scientists have discovered a distant planet with a mass of 8.2x1023 kg. The planet has a small moon that orbits with a period of 6 hours and 36 minutes. Use only this information (and the value of G) to calculate the radius of the moon's orbit (in units of 106 m).

An extrasolar planet has mass 1.27E+25 kg and radius 67400000_m. What is the escape speed for this planet? 11440_m/s 12230_m/s 5014_m/s А. D. 16190_m/s В. Е. 1973_m/s С. F. 9206 m/s

When a falling meteor is at a distance 3.58times the radius of the Earth above theEarth’s surface, what is its free-fall acceleration? The acceleration of gravity is9.8 m/s squared. , the universal gravitational constant is 6.67259×10−11 N · m2/kg2 and the Earth’sradius is 6.37 × 106 m. Answer in units of m/s 2.

A 4.00 x 10^8 kg mass and 5.00 x 10^8 kg mass are separated by a distance of 2.0 km. What is the gravitational force of attraction between the masses?

The gravitational force of attraction between any two point masses is attractive and the magnitude: Gm₂m₂ G = 6.67 x 10-11 N-m² kg² F= where G is the gravitation constant, m, and m₂ are the masses, and r is the distance between the masses. This is quite different from the force of gravity that we have been using, where weight = mg. 1. Acceleration due to gravity: a. Lett one mass be the Earth and the other mass m is let go just above the surface of the Earth. Calculate the value of the acceleration due to gravity using Newton's law of gravitation. The net effect of the Earth's gravity is the same as if the all the mass of the Earth were concentrated at its center. b. The F-22 Raptor fighter jet has a service ceiling of 12 miles or 20 km. Determine the acceleration due to gravity at this altitude. c. The International Space Station is in low Earth orbit at a height of 400 km above the surface of the Earth. Determine the acceleration due to gravity at this altitude. d. What is assumed…