A horizontal spring with force constant k = 665 N/m is attached to a wall at one end and to a block of mass m = 2.35 kg at the other end that rests on a horizontal surface. The block is released from rest from a position 4.30 cm beyond the spring's equilibrium position. (a) If the surface is frictionless, what is the speed of the block as it passes through the equilibrium position? m/s (b) If the surface is rough and the coefficient of kinetic friction between the box and the surface is ?k = 0.300, what is the speed of the block as it passes through the equilibrium position? m/s

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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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A horizontal spring with force constant 

k = 665 N/m

 is attached to a wall at one end and to a block of mass 

m = 2.35 kg

 at the other end that rests on a horizontal surface. The block is released from rest from a position 4.30 cm beyond the spring's equilibrium position.

(a) If the surface is frictionless, what is the speed of the block as it passes through the equilibrium position?
 m/s

(b) If the surface is rough and the coefficient of kinetic friction between the box and the surface is 
?k = 0.300,
 what is the speed of the block as it passes through the equilibrium position?
 m/s
Expert Solution
Step 1

a)

Apply the energy conservation equation and substitute the required values to calculate the speed of the block.

KE=SE12mv2=12kx2mv2=kx2(2.35 kg)v2=(665 N/m)(4.30 cm×1 m100 cm)2v=0.72 m/s

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