A high-impulse universal testing machine is being used to determine the Young's Modulus of a rectangular solid specimen (l = 20 cm, t = 1.5 cm, w = 2 cm). The machine produces 35,000 Ns that causes the impact force of compression resulted to a 1 mm deformation in the length of the specimen in 0.05 s. Determine the Young's modulus of the specimen expressed in MPa. Round off your answer to the nearest whole number

(i) Give the correct number of significant figures for: 4500 0.0032 0.04050 (ii) Write in scientific notation and engineering notation: 0.000467 32000000

In a tensile test for an aluminum alloy, the sample used is 2 inches long and 0.5 inches in diameter. The proportional portion of the tension stress-strain diagram for an aluminum alloy is shown below. _x106 lb/in² Pay attention to units and calculate your answer to 1 decimal place for the unit specified above. σ (ksi) 70 t 0.00614 Determine the modulus of elasticity for this material: € (in./in.)

For a given homogeneous, isotropic, linearly elastic material, E = 15e6 psi and v = 0.3. Solve for the shear modulus. 2.1.1 Homogeneous, isotropic, linearly elastic materials For specimens undergoing small deformations, the stress-strain diagram often ex- hibits a linear behavior. Although this is a very crude approximation to the behavior of actual materials, it is a convenient assumption that is often used for preliminary evaluation. A linear relationship between stress and strain can be expressed as 01 = E €1, (2.1) where the coefficient of proportionality, E, is called Young's modulus or modulus of elasticity. Since strains are non-dimensional quantities, this coefficient has the same units as stress quantities, i.e., Pa. This linear relationship is known as Hooke's law. The elongation of a bar in the direction of the applied stress is accompanied by a lateral contraction that is also proportional to the applied stress. The resulting defor- mations for this uniaxial state of stress…