i) Give the correct number of significant figures for: 4500 0.0032 0.04050 (ii) Write in scientific notation and engineering notation: 0.000467 32000000
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(i) Give the correct number of significant figures for:
4500
0.0032
0.04050
(ii) Write in scientific notation and engineering notation:
0.000467
32000000
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- using the sine bar technique, find the value of the angle for the given data: the stacked height was composed of the following values, 30, 20, 5, 2 and 1.1 mm. The length of the sine bar is 150 mm. Support your answer by sketch.Mechanical Engineering xyz= 703 Stress, ksi (log) 72 49 35 28 10³ 8 x 10³1 10¹ 401 X 8't 49 ksi 10 ksi 401 X 9'1 35 ksi 28 ksi 105 Cycles (log) 106 19.8 The provided S-N curve shows the fatigue strength of a ferrous component with unknown geometry. 107 Given the following duty record, how much life is consumed at each stress level? 60 ksi 500 cycles 2000 cycles (600 000 + XYZ*100) cycles (15000 + XYZ) cycles 40000 cyclesMechanical Engineering The fatigue strength limit Sn (n = 106) of a steel part is 112 MPa and its ultimate tensile strength (Sy) is 385MPa. Adopting Ct = 1, and S103 = 0.9 * Su* Ct, determine: (Use two decimal places in the answers), (* is multiplication signal): a) The fatigue strength (in MPa) corresponding to a life of 40000 cycles. b) The average life in cycles that this part would last if subjected to an alternating stress of 170 MPa due to bending.
- The following are the given information of the test specimen material: Specimen Material Specimen Width (mm) Specimen Thickness (mm) Specimen Initial Length (mm) Specimen Final Length (mm) aluminium 1.5 13.5 42.4 47.5 Grip Separation 50 mm Total Elongation of the specimen is given by Elongation = i-io/io x 100 l : Final length, in m l0 : Initial length, in mHi please help with this question thank you I just can't seem to work it out even with the given formulas. Thanks! also, I have tried these but they seem to be incorrect, or maybe parts of the calculation may be incorrect since when I submit these all together and I can't really work out where I am going wrong: sigma x = 25.43 sigma y = 13.07 Txy = 49.124Simple Machines-Levers, Inclined Planes, and Pulleys Directions: Use the appropriate equation to answer the following questions. All answers should be recorded below or in your Engineering Design journal. Remember to show all work. A lever has an effort arm that is 5 meters long and a resistance (load) arm that is 3.5 meters long. How much effort is needed to lift a 100 Newton weight? 5K i). Draw the figure representing the problem ii). How much effort is needed to lift a 100 Newton weight? iii). What is the Actual Mechanical Advantage 1. 5m i) AOON 5-5m
- You have the six pieces of metal listed below plus a beaker of water containing 400. g of water. The water temperature is 21.0 °C. Metals Specific Heat (J/g. K) Mass (g) 1. Al 0.9002 100. 2. Al 3. Au 4. Au 5. Zn 6. Zn 0.9002 0.1289 0.1289 0.3860 0.3860 50. 100. 50. 100. 50. The specific heat capacity of water is 4.184 J/g °C.Answer the questions below, (Insert the numerical value only, do not use ,+, *, or /) The Relative error for your answer should be less than 0.01, which means if the answer was 50, then the error should not exceed 50*0.01= ±0.5! if the answer was 230, then the error should not exceed 230*0.01= +2 3! if the answer was 2.31467*10^ 3, then you should enter this value: 0.00231467, not this 0.0023 !!!! K2 K1 M1 fv1 M2 f(t) if M1=4, M2=3, fv1=7, K1=4, K2=6. Find the state equations for the translational mechanical system shown in Figure. [d/dt(r1) d/dt(v1) [(1.1) (1.2) (1.3) (1.4) rl (1)] (2.1) (2.2) (2.3) (2.4) (3.1) (3.2) (3.3) (3.4) [(4.1) (4.2) (4.3) (4.4)] vl * f(t)$$ $$ d/dt(r2) d/dt(v2) r2I tried 33.7oC and also 50.517oC but it still says it is incorrect (view attached screenshot). I appreciate your efforts, but unfortunately it says it is still wrong. Any more ideas of what the correct answer might be? I really want to understand how to solve this problem correctly. Thank you!
- Match the following statements with the term that best describes each statement. (Enter Number ONLY) 1) Hooke's Law 2) Creep 3) Impact Strength 4) Proportional Limit 5) Fatigue 6) Elastic The tendency of a solid material to move slowly or deform permanently under the influence of mechanical stresses below the yield strength of the material. The behavior of materials that deform when loaded but return to their original shape after the load is removed. The linear relationship between stress and strain in the elastic region below the proportional limit. The phenomenon where cracks propagate under loads less than the yield stress due to cyclic loading. The material property determined using the Charpy or Izod test. The point at which the stress vs strain becomes non-linear in an elastic material,The following graph shows a load-extension graph from a test on a polymer specimen 15mm in diameter and 45mm long. The rightmost datapoint represents the reading at the point of fracture. Load (KN) 20 15- 5- 0.2 0.4 Extension (mm) 0.6 a) 0.2% offset yield strength b) The tensile strength c) The modulus of elasticity 0.8 F Determine the following physical properties. Show all your working and express all your answers in appropriate Sl units where appropriate: 1.0 d) The % elongation e) The engineering stress at fracture f) Estimate the modulus of resilienceThe slope of the curve increases The slope of the curve decreases Vertical axis (y) 10 None of these 8 The slope of the curve will not change (5.0,5.0) 5.0 Horizontal axis (x) elasticity of curve: 0.25 This question is about the slope of a curve. The interactive above may be helpful in answering the following question. For a curve with an elasticity of 2.1, and a position of 2, as the x of point increases..... position of curve: 5 x of point: 5 Slope = 0.3