A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is less than 1.5 strokes. State Ho and H, in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed, or two-tailed. Explain your reasoning. State the null hypothesis in words and in symbols. Choose the correct answer below. O A. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at least 1.5 strokes." The nul hypothesis is expressed symbolically as. "Ho: 0215" O B. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at most 1.5 strokes." The null hypothesis is expressed symbolically as, "Họ: as15- OC. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is less than 1.5 strokes." The null hypothesis is expressed symbolically as, "Họ: a<15." OD. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not 1.5 strokes." The null hypothesis is expressed symbolically as, "Ho a+15 State the alternative hypothesis in words and in symbols. Choose the correct answer below. O A. The alternative hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not 1.5 strokes." The alternative hypothesis is expressed symbolically as, "H,: o#1.5." O B. The alternative hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is less than 1.5 strokes." The alternative hypothesis is expressed symbolically as,. "H, o<1.5." OC. The alternative hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is 1.5 strokes." The alternative hypothesis is expressed symbolically as, "H, o= 1.5." OD. The alternative hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is more than 1.5 strokes." The alternative hypothesis is expressed symbolically as, "H, o>1.5."

A golf analyst claims that the standard deviation of the​ 18-hole scores for a golfer is less than 2.9 strokes. State H0 and Ha in words and in symbols. Then determine whether the hypothesis test for this claim is​ left-tailed, right-tailed, or​ two-tailed. Explain your reasoning.   State the null hypothesis in words and in symbols. Choose the correct answer below. A. The null hypothesis expressed in words​ is, "the standard deviation of the​ 18-hole scores for a golfer is at least 2.9 strokes." The null hypothesis is expressed symbolically​ as, "H0​: σ≥2.9​." B. The null hypothesis expressed in words​ is, "the standard deviation of the​ 18-hole scores for a golfer is not 2.9 strokes." The null hypothesis is expressed symbolically​ as, ​"H0​: σ≠2.9​." C. The null hypothesis expressed in words​ is, "the standard deviation of the​ 18-hole scores for a golfer is less than 2.9 strokes." The null hypothesis is expressed symbolically​ as, "H0​: σ<2.9​." D. The null hypothesis expressed in…

Claim: The mean pulse rate (in beats per minute) of adult males is equal to 68.6 bpm. For a random sample of 158 adult males, the mean pulse rate is 67.1 bpm and the standard deviation is 11.4 bpm. Complete parts (a) and (b) below. a. Express the original cialm in symbolic form. bpm (Type an integer or a decimal. Do not round.) b. Identify the null and alternative hypotheses. Ho: bpm

Hypothesis Testing Review For each problem below, simply identify the null and alternative hypotheses. Use appropriate notation/symbols. You do not have to run any hypothesis tests, although it's good practice and I'll post answers for all of them. 1) A simple random sample of 44 men from a normally distributed population results in a standard deviation of 10.7 beats per minute. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 significance level to test the claim that pulse rates of men have a standard deviation equal to 10 beats per minute. 2) In 1997, a survey of 880 households showed that 145 of them use e-mail. Use those sample results to test the claim that more than 15% of households use e-mail. Use a 0.05 significance level.

A golf analyst claims that the standard deviation of the 18-hole scores for a golfer is at most 3.1 strokes. State Ho and H, in words and in symbols. Then determine whether the hypothesis test for this claim is left-tailed, right-tailed, or two-tailed. Explain your reasoning. ..... State the null hypothesis in words and in symbols. Choose the correct answer below. A. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is not 3.1 strokes." The null hypothesis is expressed symbolically as, "Ho: σ7 3.1." B. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at least 3.1 strokes." The null hypothesis is expressed symbolically as, "Ho: o2 3.1." C. The null hypothesis expressed in words is, "the standard deviation of the 18-hole scores for a golfer is at most 3.1 strokes." The null hypothesis is expressed symbolically as, "Ho: os3.1." D. The null hypothesis expressed in words is, "the…

A null and alternative hypothesis are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. Họ: p 2 0.4 Hạ: p < 0.4

A null and alternative hypothesis are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. Ho: Ha: p = 0.7 p = 0.7 What type of test is being conducted in this problem? A. Right-tailed test B. Two-tailed test C. Left-tailed test 20

NEED HELP WITH: A,B,C please thanks