A study by researchers at a university addressed the question of whether the mean body temperature of an animal is 99.8°F. Among other data, the researchers obtained the body temperatures of 100 healthy animals. Suppose you want to use those data to decide whether the mean body temperature of healthy animals differs from 99.8°F. Complete parts (a) through (c) below. a. Determine the null hypothesis. HoiH (Type an integer or a decimal. Do not round.)

This is a Statistics problem. Please code in R.

Do various occupational groups differ in their diets? A British study of this question compared 98 drivers and 83 conductors of London double-decker buses. The conductors' jobs require more physical activity. The article reporting the study gives the data as "Mean daily consumption (+ se)." Some of the study results appear below. Drivers Total calories 2821 +44 Alcohol (grams) 0.24 0.06 Conductors 2844 +48 0.39 ± 0.11 Construct a 99% confidence interval for the difference in mean daily alcohol consumption between drivers and conductors.

A study was conducted to examine the impact of speaking in public on college students. A class of 15 statistics students participated in the study. At the beginning of a lecture the students recorded their systolic blood pressure. During the lecture the instructor called on each student to stand and answer questions about topics in the lecture. After speaking the students once again recorded their blood pressure. The resulting values are given below along with summary statistics. before 100 123 128 125 136 108 130 113 105 136 146 138 108 149 132 after 141 142 146 136 144 111 132 114 103 133 140 130 100 133 113 difference -41 -19 -18 -11 -8 -3 -2 -1 2 3 6 8 8 16 19   before after difference mean 125.1 127.9 -2.733 st dev 15.26 15.45 15.23 Does this information indicate that blood pressure increased because of speaking? Conduct an appropriate hypothesis test and show appropriate steps. Let μ1 mean systolic blood pressure before speaking in public, and μ2 mean…

A running coach wants to know if participating in weekly running clubs significantly improves the time to run a mile. The running coach collects mean mile times for 42 runners who participate in weekly running clubs with 54 runners who do not run in clubs. The running coach measures times in January and June of the same year. All times are in seconds, and the runners all started with mile times between 8 minutes (480 seconds) and 9 minutes (540 seconds). Here are the results: (table)   The running coach investigates if runners in a running club improve times more than runners not in a club. The running coach conducts a hypothesis test for the difference in sample mean change (“Running Club” minus “Not in a Club”). Here are the results: T-value = 2.7027, p-value = 0.0043, DF = 74 95% Confidence Interval (0.5254, 3.4746) Which of the following can the running coach conclude?  Runners who participate in running clubs have a statistically significant change in running times when compared…

Statistics Question

Read the scenario below. Identify the population and sample. Then determine if the bolded value is a parameter or a statistic. Use the appropriate symbol in your answer. A 1993 survey conducted by the Richmond Times-Dispatch one week before Election Day asked voters which candidate for the state's attorney general they would vote for. 37% of the respondents said they would vote for the Democratic candidate. On Election Day, 41% actually voted for the Democratic candidate. The population is The sample is This is a scenario involving The symbol goes with 37% because 37% is a The symbol v goes with 41% because 41% is a

Consider a binomial experiment with 15 trials and probability 0.45 of success on a single trial. Use the normal distribution to approximate the probability of exactly 10 successes. (Round your answer to four decimal places.)0.050

A company claims they produce their mixed bag of candies so that, of the candies in the bag, 20 percent are dark chocolate, 60 percent are milk chocolate, and 20 percent are white chocolate. In a random sample of candies of size 50, the counts are as follows: 6 dark, 32 milk, and 12 white. Assuming the conditions for inference are met, what is the test statistic for a chi-square goodness-of-fit test to investigate whether the distribution of the sample is consistent with the company’s claim? χ2=62+322+122χ2=62+322+122 A χ2=102+302+102χ2=102+302+102 B χ2=(6−10)2+(32−30)2+(12−10)2χ2=(6−10)2+(32−30)2+(12−10)2 C χ2=(6−10)210+(32−30)230+(12−10)210χ2=(6−10)210+(32−30)230+(12−10)210 D χ2=(10−6)26+(30−32)232+(10−12)212 E

please help me fix this issue, using the =t.inv on excel is giving me -2.406 can -2.047 be a typo?? thanks