A gold wire 5.45 m long and of diameter 0.890 mm carries current of 1.25 A. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Electrical hazards in heart surgery. Part A Find the resistance of this wire. Express your answer in ohms. R = Submit Part B IVE ΑΣΦ V = Request Answer Find the potential difference between its ends. Express your answer in volts. 15. ΑΣΦ ? ? V

A gold wire 5.45 m long and of diameter 0.890 mm carries current of 1.25 A. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Electrical hazards in heart surgery. Part A Find the resistance of this wire. Express your answer in ohms. R = Submit Part B IVE ΑΣΦ V = Request Answer Find the potential difference between its ends. Express your answer in volts. 15. ΑΣΦ ? ? V

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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moodle.nct.edu.om/m arning Portal Courses Reports e-Services - Academic Departments ETC CIMS - äö pio Moving Forward purses / PHYS1100 / Homework No.2/ Homework No.2 An iron wire has a diameter 3.05 mm and resistivity 9.71x 10-8 Qm. What will be the length of this wire to make a resistance of 302. What will be the new resistance, if the radius is doubled? (a) Length of the wire (in m) = (b) Resistance of the wire (in )N = Next page Upload your Homework 2 Answer - Jump to.. pad - Quiz-2 OneDrive CH6VZR403C NG 4) G E DELL
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