A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.540 and is submerged in water, which has an index of refraction of1.333. What is the critical angle (in degrees) for the light ray to remain inside the fiber?O You are working in a fiber optics manufacturing facility. Your supervisor shows you a design for an optical fiber of the construction shown in the figure below.Glass orplastic coreCladdingJacket= 1.59 and n cladcoreThe indices of refraction for the fiber are n1.58, and the radius of the fiber is 60.0 µm. While you think about these values, your supervisor asks you tocalculate the modal dispersion for a length L = 20.0 km of this optical fiber, and then leaves to go to lunch. You've heard about dispersion, but what's modal dispersion for an opticalfiber? Grabbing your smartphone, you look up modal dispersion and find that it is the time interval between arrivals of two light pulses at the far end of an optical fiber that areincident simultaneously on the near end. The first pulse enters the near end of the fiber at normal incidence to the flat end of the fiber. The second pulse enters at an incidence anglethat will result in the pulse always reflecting from the core-cladding interface of the perfectly straight fiber at the critical angle for the interface. (Enter the modal dispersion inseconds.)

Given data: The index of refraction of fiber (n1) = 1.540 The index of refraction of water (n2) =…

A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.540 and is submerged in water, which has an index of refraction of 1.333. What is the critical angle (in degrees) for the light ray to remain inside the fiber?

A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.540 and is submerged in water, which has an index of refraction of 1.333. What is the critical angle (in degrees) for the light ray to remain inside the fiber?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

Problem 9: A ray of light is incident on an air/water interface. The ray makes an angle of θ1 = 29 degrees with respect to the normal of the surface. The index of the air is n1 = 1 while water is n2 = 1.33. Part (a) Choose an expression for the angle (relative to the normal to the surface) for the ray in the water, θ2. Part (b) Numerically, what is the angle in degrees?
As shown in Fig, a layer of water covers a slab of material X in a beaker. A ray of light traveling upward follows the path indicated. Using the information on the figure, find (a) the index of refraction of material X and (b) the angle the light makes with the normal in the air.
Air has an index of refraction of 1.00. Water has an index of refraction of 1.33. Consider a pool of water that is perfectly calm and 3.21 meters deep. A ray of light (or a laser beam, if you like) enters the water, refracts, and ultimately hits the bottom of the pool. Find the distance between the point where the light enters the water and the point where the light hits the bottom of the pool if the angle between the ray in air and the surface of the pool is 46.4 degrees. Answer in meters.
X rays are typically used to kill off cancer cells, however an issue some radiologists run into is the damage an x-ray may do to surrounding tissue. Because of this, accuracy plays a key role in radiation therapy. Suppose you are a medical physicist, and you have been given the task of choosing a medium with a proper index of refraction to bend the x rays such that they only hit the tumor. Suppose you know that the x ray comes in at an angle of 20 degrees with respect to the normal of your second medium. You know the tumor expands out to 5 degrees on either side of the normal what is the minimum index of refraction needed for the x ray to hit the tumor
Box answers.
A ray of light crosses the boundary between some substance with n = 1.54 and air, going from the substance into air. If the angle of incidence is 29◦ what is the angle of refraction? Calculate to 1decimal.
take ur time
A beam of light passes through a .3 block of glass 10.0 cm thick, then through water for a distance of 30.5 cm, and finally through another block of glass 5.0 cm thick. If the refractive index of both pieces of glass is 1.525 and of water is 1.333, .find the total optical path
A glass optical fiber is used to transport a light ray across a long distance. The fiber has an index of refraction of 1.520 and is submerged in ethyl alcohol, which has an index of refraction of 1.361. What is the critical angle (in degrees) for the light ray to remain inside the fiber?
A ray of light hits the surface between air and an unknown material at an angle A of 58.8°. It travels through the unknown material at an angle B of 38.5° relative to the vertical. What is the index of refraction of the material?
An engineer is carrying out an experiment to determine the index of refraction for a partially reflective material. To do this, she aims a narrow beam of light at a sample of this material, which has a smooth surface. She then varies the angle of incidence. (The incident beam is traveling through air.) The light that gets reflected by the sample is completely polarized when the angle of incidence is 59.5°. (a)What index of refraction describes the material? n = (b)If some of the incident light (at ?i = 59.5°) enters the material and travels below the surface, what is the angle of refraction (in degrees)?
A light ray in glass (refractive index 1.57) arrives at the glass-water interface at an angle of 0 = 48° with the normal. The index of refraction of water is 1.33. What is the angle of refraction @ that a refracted ray makes with the normal ? water glass O 42° O 56° O 61° O 20°