A genetic experiment involving peas yielded one sample of offspring consisting of 431 green peas and 145 yellow peas. Use a 0.01 significance level to test the claim that under the same circumstances, 26% of offspring peas will be yellow. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. Use the P-value method and the normal distribution as an approximation to the binomial distribution. What are the null and alternative hypotheses? O B. Ho: p#0.26 O A. Ho: p#0.26 H:p>0.26 H;:p=0.26 C. Ho: p=0.26 H: p#0.26 OD. Ho: p=0.26 H: p>0.26 OE. Ho: p=0.26 OF. Ho: p#0.26 H:p<0.26 H:p<0.26 What is the test statistic? (Round to two decimal places as needed.)

A television show conducted an experiment to study what happens when buttered toast is dropped on the floor. When 43 buttered slices of toast were dropped, 23 of them landed with the buttered side up and 20 landed with the buttered side down. Use a 0.10 significance level to test the claim that toast will land with the buttered side down 50% of the time. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. After that, supposing the intent of the experiment was to assess the claim that toast will land with the buttered side down more than 50% of the time, write a conclusion that addresses the intent of the experiment. Let p denote the population proportion of all buttered toast that will land with the buttered side down when dropped. Identify the null and alternative hypotheses to test the claim that buttered toast will land with the buttered side down 50% of the time. Ho p = H₁ p 0.5 0.5 (Type integers or decimals. Do not round.)…

A certain drug is used to treat asthma. In a clinical trial of the drug, 17 of 278 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 10% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level. What is the final conclusion? 1-PropZTest prop <0.1 z = - 2.159136518 p= 0.0154197886 p= 0.0611510791 n = 278 O A. There is not sufficient evidence support the claim that less than 10% of treated subjects experienced headaches. O B. There is sufficient evidence support the claim that less than 10% of treated subjects experienced headaches. O C. There is not sufficient evidence to warrant rejection of the claim that less than 10% of treated subjects experienced headaches. O D. There is sufficient evidence to warrant rejection of the claim that less than 10% of treated subjects…

In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6968subjects randomly selected from an online group involved with ears. There were 1335 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution.   Identify the null hypothesis and alternative hypothesis.   A. H0​: p=0.2 H1​: p≠0.2   B. H0​: p>0.2 H1​: p=0.2   C. H0​: p=0.2 H1​: p<0.2   D. H0​: p<0.2 H1​: p=0.2   E. H0​: p≠0.2 H1​: p=0.2   F. H0​: p=0.2 H1​: p>0.2   The test statistic is z= ____ ​(Round to two decimal places as​ needed.)   The​ P-value is ____. ​(Round to three decimal places as​ needed.)

A certain drug is used to treat asthma. In a clinical trial of the drug, 18 of 282 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 11% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level. What is the final conclusion? 1-PropZTest prop < 0.11 z = -2.477964522 p=0.0066067142 p=0.0638297872 A n = 282 A. There is sufficient evidence support the claim that less than 11% of treated subjects experienced headaches. OB. There is not sufficient evidence to warrant rejection of the claim that less than 11% of treated subjects experienced headaches. OC. There is not sufficient evidence support the claim that less than 11% of treated subjects experienced headaches. D. There sufficient evidence to warrant rejection of the claim that less than 11% of treated subjects experienced…

In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6973 subjects randomly selected from an online group involved with ears. There were 1343 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. ..... Identify the null hypothesis and alternative hypothesis. А. Но: Р0.2 ОЕ. Но: р> 0.2 OF. Ho:p=0.2 H4:p=0.2 H1:p<0.2 The test statistic is z= (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) Because the P-value is the significance level, the null hypothesis. There is evidence to support the claim that the return rate is less than 20%.

When Brett Kavanaugh was nominated to be a Supreme Court justice, a survey of 1127 Americans showed that 50.6% of them disapproved of Kavanaugh. A newspaper published an article with this headline: "Majority of Americans Disapprove of Kavanaugh." Use a 0.01 significance level to test the claim made in that headline. Use the P-value method. Use the normal distribution as an approximation to the binomial distribution. tcrunch 2 W S X H and Let p denote the population proportion of all Americans who disapproved of Kavanaugh. Identify the null and alternative hypotheses. Ho: PY H₁: p < (Type integers or decimals. Do not round.) Identify the test statistic. N Z= (Round to two decimal places as needed.) Identify the P-value. P-value= (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Tech help #3 80 FS E D с 154 $ R F V % 5 T G MacBook Air B TAREHBE 9 Y H & 7 DUTO N U J 8 M ** I K H O L…

The lengths of yoga sessions in a gym follows a Normal distribution with mean 30 minutes and variance 4 minutes. The members of the gym complained that some sessions are too long and get overwhelming. To assess the situation, management randomly supervised a session. What is the probability that this yoga session lasts longer than the advised maximum 35 minutes?

In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6983subjects randomly selected from an online group involved with ears. There were 1315 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis.     A. H0​: p=0.2 H1​: p>0.2   B. H0​: p>0.2 H1​: p=0.2   C. H0​: p=0.2 H1​: p≠0.2   D. H0​: p=0.2 H1​: p<0.2   E. H0​: p<0.2 H1​: p=0.2   F. H0​: p≠0.2 H1​: p=0.2   The test statistic is z=. ​(Round to two decimal places as​ needed.)   The​ P-value is . ​(Round to three decimal places as​ needed.)   Because the​ P-value is ▼ Less than, greater than   the significance​ level, ▼   reject fail to reject   the null hypothesis. There is ▼   sufficient…