A genetic experiment Involving peas yielded one sample of offspring consisting of 422 groen peas and 149 yellow peas. Use a 0 01 significance level to test the claim that under the same circumstancas, 25% of offspring peali will be yelow Ideely the ul hypothes atemutive hypothesin, test statistk. Pvalue, conclusion about the null hypothesio, and final conclunion that addresses the original claim. Use the P-value mothod and the normal distribution as an approximation to the binomial distibution OE H pAD 25 H, p0 25 OF H p/025 H, p>025 What is the test statistic? (Round to wo decimal places as needed.) What is the Pyalue? Pvakie (Round to four decimal places as needed) What is the conclusion about the null hypothesis? CA Reject the null hypothesis because the P.value is less than or aqual to the significance level, u. OU. Reject the null hypothesis because the P-value is greater than the significance level a. OC Fal to reject the nuil hypothesis because the P-value is greater than the significance level, a. OD. Fall to reject the null hypothesis because the P-value is less than or equal to the significance lavel, a What is the final conclusion? OA There is sufficient evidence to support the claim that less than 25% of offspring peas will be yallow OB There ie not sulficiont evidence to support the claim that less than 25% of offspring peas will be yellow OC There is sufficient evidence to watrant rejection of the claim that 25% of ofispring peas will be yellow DD. There is not sufficlent evidence to warrant rejaction of the claini that 25% of offopring peas wit be yallow

A national survey conducted in 2011 among a simplerandom sample of 1507 adults shows that 56% of Americans think the Civil War is still relevant toAmerican politics and political life.  a) Conduct a hypothesis test to determine if these data provide strong evidence that the majority (> 50%)of the Americans think the Civil War is still relevant. Please calculate the test statistic, the P-value,and make a conclusion at a 1% significance level. b) Which of the following is the correct interpretation of the p-value calculated in part (a)?i. It’s the probability that the majority (> 50%) of Americans think the Civil War is still relevantto American politics and political life, given that 56% of the sample of size 1507 think so.ii. It’s the probability that that 50% of Americans think the Civil War is still relevant to Americanpolitics and political life, given that 56% of the sample of size 1507 think so.iii. It’s the probability to obtain a sample of size 1507 that 56% or more think…

2) Two groups of students were surveyed – 86 students were enrolled in a class that required the purchase of lecture notes with mean for this sample being 8.48 and sample variance 0.94. While 35 students were enrolled in another class that did not require the purchase of lecturer notes mean for this sample being 7.80 and sample variance 2.99. The students need to decide whether or not to purchase the lecture notes? a) Hypothesis testing: Do the samples provide sufficient evidence to conclude that there is a difference in the mean responses of the two groups of students? Test using a level of significance = 0.01 (1%). b) Construct a 99% confidence interval for the difference between the two samples and interpret the results. c) Calculate the P-Value and interpret.

7. A simple random sample of front-seat occupants involved in a car crashes is obtained. Among 2935 occupants not wearing seat belts, 33 were killed. Among 7813 occupants wearing seat belts, 19 were killed. Use a 0.001 significance level to test the claim that seat belts are effective in reducing fatalities. Identify the null hypothesis, alternate hypothesis, test statistic, P-value, conclusion about the null hypothesis, and conclusion that addresses the original claim.

In a study of 1228 randomly selected medical malpractice lawsuits, it was found that 856 of them were dropped or dismissed. Use a 0.01 significance level to test the claim that more than 50% of the medical malpractice lawsuits are dropped or dismissed.

Suppose 214 subjects are treated with a drug that is used to treat pain and 52 of them developed nausea. Use a 0.10 significance level to test the claim that more than 20​% of users develop nausea. i) Identify the statistic for this hypothesis ii) Determine the P-value iii) State the conclusion

In a recent court case it was found that during a period of 11 years 870 people were selected for grand jury duty and 37​% of them were from the same ethnicity. Among the people eligible for grand jury​ duty, 79.6​% were of this ethnicity. Use a 0.05 significance level to test the claim that the selection process is biased against allowing this ethnicity to sit on the grand jury. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution. a. What is the test​ statistic? z equals ​(Round to two decimal places as​ needed.)   b. What is the​ P-value? ​P-value equals ​(Round to four decimal places as​ needed.)

Since an instant replay system for tennis was introduced at a major tournament, men challenged 1386 referee calls, with the result that 421 of the calls were overturned. Women challenged 745 referee calls, and 222 of the calls were overturned Use a 0.05 significance level to test the claim that men and women have equal success in challenging calls, Complete parts (a) through (e) below.

According to a Pew Research Centernationwide telephone survey of adults conducted between March 15 and April 24, 2011.55% of college graduates said that college education prepared them for a job Time. May 30, 2011Suppose this result waste of all college graduates allhat sample 1850 college graduates 60% said that college education prepared them for job there significant evidence at a 2% significance level to conclude that the current percentage of all college graduates who will that college education prepared them for a job is different from 55% Use both the p-value and the critical-value approaches Round your answers for the observed value of zand the critical value of decimal places, and the pvalue to four decimal places Enter the critical values in increasing order p-valve = Z Observed = critical values=  ( ) and ( ) We can conclude that the current percentage of all college graduates who will say that college education prepared them for the job       55 %