A frequency filter (different from the previous problem) is shown below. K Vout -0000 a) Derive an expression for Vout/V, as a function of the angular frequency w of the voltage source. b) Show that when w→0, Vout/V. 1. This means that the low frequencies pass. c) Show that when woo, Vout/V→ 0. This means that the high frequencies do not pass.

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Problem 10
A frequency filter (different from the previous problem) is shown below.
V
a) Derive an expression for Vout/V, as a function of the angular frequency w of the voltage
source.
b) Show that when w→0, Vout/Vs →1. This means that the low frequencies pass.
c) Show that when woo, Vout/Vs → 0.
This means that the high frequencies do not pass.
Transcribed Image Text:Problem 10 A frequency filter (different from the previous problem) is shown below. V a) Derive an expression for Vout/V, as a function of the angular frequency w of the voltage source. b) Show that when w→0, Vout/Vs →1. This means that the low frequencies pass. c) Show that when woo, Vout/Vs → 0. This means that the high frequencies do not pass.
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