A foot powder sample containing Zn was dissolved on 50.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (as= 3.61x10-9, KZnY2- = 3.2 × 1016). The pZn in the sample is: Please fill in the space with a numerical value with two digits or two decimal places without units
Q: A 140.0 mL sample of 0.070 M Ca²+ is titrated with 0.070 M EDTA at pH 9.00. The value of log Kf for…
A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…
Q: For the titration of 50.00 mL of 0.000226 M Ba²* with 0.100 M EDTA at pH 10.00, ay = 0.30, and Kf =…
A:
Q: Calculate pAl when 25 mL of 0.0274 M Al3+ solution was titrated with 28 mL 0.0180 M EDTA at pH 5.…
A: 25 mL of 0.0274 M Al3+ solution was titrated with 28 mL of 0.0180 M EDTA at pH 5 .log Kf = 16.4…
Q: The Cr plating on a surface that measured 3.00 cm x 4.00 cm was dissolved in HCl. The pH was…
A: Given : molarity of EDTA : 0.01441M Volume of EDTA = 10.19mL Total amount of EDTA or milimole of…
Q: A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid…
A: This classical method of determination of Hardness of water by titration of Standard and unknown…
Q: A 150.0 mL sample of 0.080 M Ca2+ is titrated with 0.080 M EDTA at pH 9.00. The value of log Kf for…
A: Given that : The volume of the Ca2+ sample = 150.0 mL Molarity of the Ca2+ sample = 0.080 M Molarity…
Q: 2. After preparing the buffer, they decided to determine the buffer capacity of the solution by…
A: Buffer capacity can be expressed as:
Q: 5. 20 mL of tap water sample is taken in a conical flask and 1 mL of pH 10 buffer and 3 drops of…
A: Hard water is the water that contains dissolved Ca2+ and Mg2+ ions. These ions react with fatty…
Q: A deep well sample of 100 mL was titrated with 0.010 M EDTA at pH=10 (with Mg-EDTA-pH 10 reagent)…
A:
Q: A 14.92 g sample of bacon was pureed in a blender with 100.0 mL of water. The suspension was…
A:
Q: A 60.00 mL of buffered solution (pH 10) containing Zn2* and Ni2* ions (from a chip sample) is…
A: Metal ion combine with EDTA in 1 : 1 mole ratio. So we would calculate moles of both metal ions…
Q: solution is mixed with 40.00 mL of 1.2% (w/v, g/mL) Na2CO3 solution. What volume of 0.087 M HCl will…
A: The question is based on the concept of titrations. we are titrating a mixture of bases with a…
Q: A 100.0 mL100.0 mL solution of 0.0200 M Fe3+0.0200 M Fe3+ in 1 M HClO41 M HClO4 is titrated with…
A: The Nernst equation is shown below: Where; Ecell = electrode potential at any condition E0cell =…
Q: A 50.00 mL sample of water was collected from a faucet. A 10.00 mL aliquot of this sample was placed…
A: EDTA and Ca+2 forms 1:1 complex Number of moles of standard EDTA consumed = molarity * volume =…
Q: A solution prepared by mixing 22.2 mL of 0.400 M NaCl and 22.2 mL of 0.400 M KI was titrated with…
A:
Q: An EDTA solution is standardized against high-purity CaCO3 by dissolving 0.3982 g CaCO3 in…
A: Given, CaCO3=0.3982 g Volume of EDTA =38.26 mL molecular weight of EDTA= 292.24 g/mol
Q: A solution prepared by mixing 22.2 mL of 0.400 M NaCl and 22.2 mL of 0.400 M KI was titrated with…
A: Answer is 7.48 x 10-16 M .
Q: culate the fraction of EDTA that exists as fully deprotonated anion Y" at pH 7.0. idity constants of…
A: Hello. Since multiple questions have been posted, the first question shall only be solved in this…
Q: The Tl in a 9.76-g sample of rodenticide was oxidized to the trivalent state and treated with an…
A: a) Direct titration In direct titration , a titrant of known concentration and volume is added to a…
Q: Given the approximate Kf values: Ca-EDTA = 1010 ; Mg-EDTA = 10 ; Fe-EDTA = 1014 ; Hg-EDTA = 1021;…
A: Correct answer (B)
Q: A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid…
A: Given data; Mass of solid CaCO3 is 3.1251 g The volume of dilute HCl for prepare CaCO3 solution is…
Q: In order to titrate EDTA into a water sample of unknown water hardness, the EDTA of known…
A:
Q: 20.0 mL portion of a deep well water sample was diluted to 250.00 mL solution. A 50.0 mL aliquot of…
A: The question is based on the concept of complexometric titrations. we have to titrate given water…
Q: Solution made by mixing 5mL of 0.030M Co2(SO4)3 with 40mL of 0.0120M EDTA was adjusted to pH 10.…
A: Given: Concentration of Co2(SO4)3 = 0.030 M Volume of Co2(SO4)3 = 5 mL Concentration of EDTA =…
Q: A 100.0 mL sample of drinking water was buffered at pH 10.0 and, after addition of Calmagite…
A:
Q: A soil was measured for cation exchange by leaching 15 g of soil with 80 mL of solution of 1 M…
A:
Q: Calculate the pZn2+ for solutions prepared by adding 0.00, 5.00, 10.00, 15.00, 20.00, 25.00 and…
A: The concentration of Zn2+ can be determined as: M1V1(Zn2+)=M2V2(EDTA) pZn2+ can be determined by:…
Q: The Tl in a 9.76-g sample of rodenticide was oxidized to the trivalent state and treated with an…
A: In the reaction, all of the 1 Tl3+(aq) is converted to 1 TlY-(aq) and 1 Mg2+(aq). Hence the moles of…
Q: Calculate the concentration of Ni²+ and pNi in a solution that was prepared by mixing 50.0 mL of…
A: Solution: We have to calculate the unknown concentration of Ni2+
Q: Given: Keff of MgY² = 1.7 x 108 at pH 10.0. When 25.0 mL of 0.0100 M Mg2+ is mixed with 25.0 mL of…
A: The balanced equation for the titration reaction is: Mg2+(aq) + Y4-(aq) ⇌ MgY2-(aq) ; Keff = 1.7*108…
Q: .. Tris(hydroxymethyl)aminomethane abbreviated as Tris or TRIŽMA is frequently used to make buffers…
A: Hasselbach Henderson equation pH = pKa+ log ([Salt][Acid]) * pKa= 8.10 * We will use 1.0 M HCl to…
Q: A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid…
A: Given data contains, Mass of solid CaCO3 is 3.1251g. Volume of dilute hydrochloric acid for…
Q: In an unprecedented initiative, the professor chose you to carry out the determination of a special…
A: Fe(III) salts are titrated against EDTA using SCN- indicator.
Q: A foot powder sample containing Zn was dissolved on 50.00 ml water and was titrated to the end point…
A:
Q: Use a spreadsheet and construct curves for the follow- ing titrations. Calculate potentials after…
A: Solution a) Half-cell reactions involved are:
Q: A 1.509-g samle of a Pb/Cd alloy was dissolved in acid and diluted to exactly 250.0 mL in a…
A: The explanation is given below-
Q: Consider the titration of 25.00 mL of 0.0900 M HNO3 with 0.0750 M KOH. HNO3 + KOH KNO3 - Calculate…
A: mmoles of HNO3 taken for titration = C*V = 0.0900 molL * 25.00 mL = 2.25 mmol Required mole ratio in…
Q: A water sample was tested for water hardness. A 50.00 mL sample, prepared and buffered to pH 10,…
A: Calculate number of moles of EDTA: 1 mL = 0.001 L No.of moles=Molarity×Volume…
Q: In a solution kept constant by buffering to pH= 8.0, 50.0 mL of 0.0050 M Ni2+ is 0,0100 İn titration…
A: The question is based on the concept of quantitative analysis. We have to calculate pNi at different…
Q: A foot powder sample containing Zn was dissolved on 100.00 mL water and was titrated to the end…
A: The question is based on the concept of complexometric titrations. We have to calculate P value of…
Q: In a solution kept constant by buffering to pH= 8.0, 50.0 mL of 0.0050M Ni2+ is 0,0100 In titration…
A: The question is based on the concept of complexometric titrations. We have to calculate pNi at…
Q: The calcium content of a milk sample was to be determined by EDTA titration. A sample weighing 0.206…
A:
Q: A standard CaCO3 solution is prepared by dissolving 0.4193g in enough dilute HCl to effect solution…
A: The given data contains, weight of CaCO3 =0.4193 g volume of EDTA =23.62 ml
Q: To a 50.00-mL aqueous solution containing Pb2+ is added a total amount of 5.000 mmol EDTA. The pH…
A: This is a method of quantitative estimation of concentration of unknown solution by titrating it…
Q: A deep well sample of 100 mL was titrated with 0.010M EDTA at pH = 10 (with Mg-EDTA-pH10 reagent)…
A: Solution -
Q: An unknown solution containing 25.00 mL of Ni2+ in dilute HCl is treated with a known excess of…
A: Given, Ni2+=25.0 mLEDTA= 25.0 mLConcentration of EDTA =0.05382 MZn2+=0.02299 MVolume= 17.0 mL
Q: A 1.000 ml aliquot of a solution containing Cu* and Ni* is treated with 25.00 mL of a 0.03468 M EDTA…
A: EDTA is Ethylenediamine tetra acetic acid which is used as a chelating ligand. The balanced chemical…
Q: Consider the titration of 25.0 mL of 0.0100 M Sn²+ by 0.0500 M TI³* in 1M HCl using Pt and an SCE…
A: Answer
Q: 1. Tris(hydroxymethyl)aminomethane abbreviated as Tris or TRIŽMA is frequently used to make buffers…
A: Tris is a base that is used in the preparation of buffer. The buffer that can be prepared from tris…
Step by step
Solved in 2 steps with 3 images
- A foot powder sample containing Zn was dissolved on 200.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (as= 3.61x10-9, K ZnY2- = 3.2 × 1016). The pZn in the sample %3D is: Please fill in the space with a numerical value with two digits or numerical values without unitsA foot powder sample containing Zn was dissolved on 200.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61x10-9, K ZnY2- = 3.2 x 1o16). The pzn in the sample is: Please fill in the space with a numerical value with two digits or numerical values without units Answer:A foot powder sample containing Zn was dissolved on 100.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (as= 3.61×10-9, KZnY2- = 3.2 x 1016). The pZn in the sample is: Please fill in the space with a numerical value with two digits or two decimal places without units
- A foot powder sample containing Zn was dissolved on 50.00 ml water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61x10-9, KZNY2- = 3.2 x 1016). The pZn in the sample is: Please fill in the space with a numerical value with two digits or two decimal places without units Answer:A foot powder sample containing Zn was dissolved on 50.00 ml water and was titrated to the end point color with 22.57 mL of 0,01639 M EDTA at pH=D4. (a4=3,61×10, KZNY = 3.2 x 10") The pzn in the sample is Please fill in the space with a numerical value with two digits or two decimal places without unitsA foot powder sample containing Zn was dissolved on 100.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61x10-9, KZnY2- = 3.2 × 1016). The pzn in the sample is: Please fill in the space with a numerical value with two digits or two decimal places without units
- A foot powder sample containing Zn was dissolved on 100.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 .M EDTA at pH=4 a4= 3.61×10-9, KZNY²- = 3.2 x) :1016). The pZn in the sample is %3DA foot powder sample containing Zn was dissolved on 200.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61x10-9, K ZnY²- = 3.2 × 1016). The pZn in the sample is: %3D Please fill in the space with a numerical value with two digits or numerical values without units Answer:Solutions of cobalt (II) ions have a magenta color with a molar absorptivity constant (e) value at 511 nm of 5.87 M-1cm-1. A 0.500 mL sample is transferred from a 50.0 mL stock solution of Co(NO3)2 and diluted with water to a final volume of 7.50 mL. The dilution had an absorbance value at 511 nm in a standard cuvette (1.00 cm light path) of 0.382. Calculate the mass of Co(NO3)2 contained in the original 50.0 mL stock solution.
- A foot powder sample containing Zn was dissolved on 50.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (α= 3.61x109, KKzny2 = 3.2 x 1016). The pZn in the sample is:A cyanide solution with a volume of 12.99 ml was treated with 30.00 ml. of Ni" solution (containing excess Nit) to convert the cyanide into tetracyanonickelate(): 4 CN + Ni?+ Ni(CN) The excess Nit was then titrated with 11.96 ml. of 0.01357 M ethylenediaminetetraacetic acid (EDTA): Nit + EDTA Ni(EDTA)- Ni(CN) does not react with EDTA. If 39.40 ml. of EDTA were required to react with 30.65 ml. of the original Nit solution, calculate the molarity of CN in the 12.99 mL cyanide sample. 0.12055 (CN = IncorvectA 0.3045 g of CaCO3 primary standard was dissolved using concentrated HCl, evaporated to incipient dryness and quantitatively transferred to a 250 mL volumetric flask, and diluted to mark. A 10 mL of aliquot was then transferred to an Erlenmeyer flask, together with 5mL buffer and 5 drops of EBT indicator, and was used to standardize the EDTA titrant. The solution turned blue after the addition of 24.10 mL of EDTA. A blank correction was performed and was determined to be 0.4 mL. What is the concentration of EDTA obtained (MW CaCO3 = 100.0869 g/mol)?