A foot powder sample containing Zn was dissolved on 50.00 ml water and was titrated to the end point color with 22.57 ml of 0,01639 M EDTA at pH=D4. (a4= 3.61×10 , KZnY2 = 3.2 x 10). The pZn in the sample is
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- The equilibrium constant for the conjugate acid-base pair HIn+H2OH3O++In is 8.00 10-5. From the additional information in the following table, (a) calculate the absorbance at 430 nmand 600 nm for the following indicator concentrations: 3.00 10-4M,2.00 10-4M, 1.00 10-4M, 0.500 10-4 M, and 0.250 10-4M. (b) plot absorbance as a function of indicator concentration.A foot powder sample containing Zn was dissolved on 200.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61x10-9, K ZnY2- = 3.2 x 1o16). The pzn in the sample is: Please fill in the space with a numerical value with two digits or numerical values without units Answer:A foot powder sample containing Zn was dissolved on 50.00 ml water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61x10-9, KZNY2- = 3.2 x 1016). The pZn in the sample is: Please fill in the space with a numerical value with two digits or two decimal places without units Answer:
- A foot powder sample containing Zn was dissolved on 100.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 .M EDTA at pH=4 a4= 3.61×10-9, KZNY²- = 3.2 x) :1016). The pZn in the sample is %3DA foot powder sample containing Zn was dissolved on 200.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61x10-9, K ZnY²- = 3.2 × 1016). The pZn in the sample is: %3D Please fill in the space with a numerical value with two digits or numerical values without units Answer:A foot powder sample containing Zn was dissolved on 100.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (a4= 3.61x10-9, KZnY2- = 3.2 × 1016). The pzn in the sample is: Please fill in the space with a numerical value with two digits or two decimal places without units
- A foot powder sample containing Zn was dissolved on 200.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (as= 3.61x10-9, K ZnY2- = 3.2 × 1016). The pZn in the sample %3D is: Please fill in the space with a numerical value with two digits or numerical values without unitsA foot powder sample containing Zn was dissolved on 100.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (as= 3.61×10-9, KZnY2- = 3.2 x 1016). The pZn in the sample is: Please fill in the space with a numerical value with two digits or two decimal places without unitsSolutions of cobalt (II) ions have a magenta color with a molar absorptivity constant (e) value at 511 nm of 5.87 M-1cm-1. A 0.500 mL sample is transferred from a 50.0 mL stock solution of Co(NO3)2 and diluted with water to a final volume of 7.50 mL. The dilution had an absorbance value at 511 nm in a standard cuvette (1.00 cm light path) of 0.382. Calculate the mass of Co(NO3)2 contained in the original 50.0 mL stock solution.
- A foot powder sample containing Zn was dissolved on 50.00 mL water and was titrated to the end point color with 22.57 mL of 0.01639 M EDTA at pH=4. (α= 3.61x109, KKzny2 = 3.2 x 1016). The pZn in the sample is:A CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid CaCO3 in 100 mL dilute HCl. A 20.00 mL aliquot was taken for titration with EDTA consuming 32.00 mL of the titrant to reach the endpoint. Express the concentration of EDTA in molarity and in CaCO3 titer.MM Na2H2Y2•2H2O = 372.24 g/mole; MM CaCO3 = 100.09 g/moleA CaCO3 solution that will be used to standardize EDTA was prepared by dissolving 3.1251 g of solid CaCO3 in 100 mL dilute HCl. A 20.00 mL aliquot was taken for titration with EDTA consuming 32.00 mL of the titrant to reach the endpoint. Express the concentration of EDTA in molarity and in CaCO3 titer. MM Na2H2Y2•2H2O = 372.24 g/mole; MM CaCO3 = 100.09 g/mole