A flywheel whose moment of inertia /= 200 lb-ft2 is spinning at 180 RPM. For a flywheel, KE = Iw2/2, where w is the angular velocity,rad/s. Let g = 32.2 ft/s².Step 1How high above the surface of the earth, in ft, would a 60 lb mass have to be raised to have its potential energy equal to the kineticenergy of the flywheel?h = ift

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Answered: A flywheel whose moment of inertia / =…

A flywheel whose moment of inertia / = 200 lb-ft² is spinning at 180 RPM. For a flywheel, KE = Iw²/2, where w is the angular velocity, rad/s. Let g = 32.2 ft/s².

College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Question

A flywheel whose moment of inertia /= 200 lb-ft2 is spinning at 180 RPM. For a flywheel, KE = Iw2/2, where w is the angular velocity,
rad/s. Let g = 32.2 ft/s².
Step 1
How high above the surface of the earth, in ft, would a 60 lb mass have to be raised to have its potential energy equal to the kinetic
energy of the flywheel?
h = i
ft

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