Two independent samples have been selected, 88 observations from population 1 and 72 observations from population 2The sample means have been calculated to be 7₁ = 6.7 and 7₂ = 9.6.From previous experience with these populations, it is known that the population variances are 0 = 39 and o2 = 33.You hypothesize that the two samples come from different normal distributions. Specifically, your Null hypothesis is Ho: (1= 2) andH₁: (4₁> H₂)(a) Find (71-72)answer:(b) Determine the rejection region for the test of Ho: (H1-H2) = 2.46 and H₁ (1-2) > 2.46 Use ax = 0.01.z>(c) Compute the test statistic.T =The final conclusion isA. We can reject the null hypothesis that (1-2) = 2.46 and accept that (₁-₂) > 2.46.B. There is not sufficient evidence to reject the null hypothesis that (1-2)=2.46.(d) Construct a 99 % confidence interval for (#1 - 1₂).≤ (14-1₂) ≤

Given that, Population 1 Population 2 n1=88 n2=72 x¯1=6.7 x¯2=9.6 s12= 39 s22 = 33 The…

Answered: (a) Find (71-72) answer: (b) Determine…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(d) A random sample consists of a single observation, r, from the Bin(6, 7) distribution, i.e. a binomial distribution with six trials. We are interested in testing: Ho = 0.50 vs. H₁: π = 0.75. A test rejects Ho if x = 6. i. Calculate the size of the test. ii. Calculate the power of the test.
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A hypothesis test is conducted with H0:μ=55 and H1:μ>55 A simple random sample of size n=64 is drawn, with x¯=62, and s=18.Compute the test statistic. (Round to two decimal places.) Determine the P-value. (Round to four decimals places.)
TF.16 A random sample of size 50 is used to test the null hypothesis H0 : μ = 5.5 (the average monthly salary in thousands of dollars ($5,500) for new assistant professors) against Ha : μ > 5.5. The sample mean is x̄ = 5.75, and the population standard deviation is σ = 0.85. Test H0 against Ha at α = 0.01 level of significance. Find the p-value.
(c) In an experiment, the weight of the subatomic particles was measured repeatedly, producing the following values: 45, 47, 43, 54, 38, 45 and 58 mg. By using the statistical method, report the best estimated value of weight of the particles within uncertainty (+1 standard deviation). Where E(wavg-w1) the uncertainty in weight is ow and standard deviation, w = N is the number N-1 of trials.
I want to know the answer and detail step by step
You run a regression analysis on a bivariate set of data (n=82n=82). You obtain the regression equationy=4.373x+9.596y=4.373x+9.596with a correlation coefficient of r=0.987r=0.987 (which is significant at α=0.01α=0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 60 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)
(d) Use a t-test to test if the relationship between years of experience and income is statistically significant at the 0.05 level of significance. State the null and alternative hypotheses. O Ho: B₁ ≥ 0 H₂: B₁< < 0 Ho: B₁ = 0 Ha: B₁ * 0 O Ho: B₁ * 0 Ha: B₁ = 0 о ново = 0 Ha: Bo # 0 Ho Bo # 0 Ha: Bo Find the value of the test statistic for the t-test. (Round your answer to three decimal places.) = = 0 Find the p-value. (Round your answer to four decimal places.) p-value What is your conclusion? O Reject Ho. We conclude that the relationship between years of experience and income is significant. O Do not reject Ho. We cannot conclude that the relationship between years of experience and income is significant. O Reject Ho. We cannot conclude that the relationship between years of experience and income is significant. O Do not reject Ho. We conclude that the relationship between years of experience and income is significant. (e) Calculate the coefficient of determination. (Round your…
q-9
Q1:Let p equal the proportion of drivers who use a seat belt in a country that does not have a mandatory seat belt law. It was claimed that p = 0.14. An advertising campaign was conducted to increase this proportion. Two months after the campaign, y = 104 out of a random sample ofn = 590 drivers were wearing their seat belts. The null and alternative hypotheses are given by
Let μ denote the average resting heart rate for a healthy female. For a large-sample z test of Ho: μ = 80 versus H: μ< 80, find the P-value associated with each of the given values of the z test statistic. (Round your answers to four decimal places.) (a) -0.51 (b) -0.94 (c) -1.95 (d) -2.27 (e) 1.30
'eriod: 1. A random sample of 100 voters in a community produced 59 voters in favor of Candidate A. The observed value of the test statistic for testing the null hypothesis : p=0.5 versus the H.:p>0.5 is alternative hypothesis (a) Date: z = [(0.59-0.5)/√(0.59)(0.41)/100 t=[(0.59-0.5)/√(0.59)(0.41)/100] (b) z=[(0.59-0.5)/√(0.5)(0.5)/100 =[(0.59-0.5)/√(0.5)(0.5)/100] (c) (e) None of these 2. In a test of H: p = 0.7 against H: p* 0.7, a sample of size 80 produces z = 0.8 for the value

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