A fast food restaurant estimates that the mean sodium content in one of its breakfast sandwiches is no more than 920 milligrams. A random sample of 30 breakfast sandwiches has a mean sodium content of 910 milligrams. Assume the population standard deviation is 25 milligrams. At α = 0.10, do you have enough evidence to reject the restaurant's claim? Complete parts (a) through (e).(a) Identify the null hypothesis and alternative hypothesis.- A. $ H_0: \mu \leq 910 $ $ H_a: \mu < 910 $ (claim)- B. $ H_0: \mu = 910 $ (claim) $ H_a: \mu \neq 910 $- C. **$ H_0: \mu \leq 920 $ (claim) $ H_a: \mu > 920 $**- D. $ H_0: \mu > 920 $ $ H_a: \mu \leq 920 $ (claim)- E. $ H_0: \mu < 910 $ (claim) $ H_a: \mu \geq 910 $- F. $ H_0: \mu \neq 920 $ (claim) $ H_a: \mu = 920 $(b) Identify the critical value(s). Use technology.$ z_0 = 1.28 $(Use a comma to separate answers as needed. Round to two decimal places as needed.)Identify the rejection region(s). Select the correct choice below.- **A. The rejection region is $ z > 1.28 $.**- B. The rejection region is $ z < 1.28 $.- C. The rejection regions are $ z > 1.28 $ and $ z < -1.28 $.(c) Identify the standardized test statistic. Use technology.$ z = $ (Round to two decimal places as needed.)

Claim of the problem: The mean sodium content in one of its breakfast sandwiches is no more than 920 milligrams. H0:μ≤920Ha:μ>920 Given α=0.10 Here, the tail of the test is right tail. z critical value=1.28, obtained by excel function, =NORM.INV(1-0.1=0.99,0,1) Rejection Rule: Reject the null hypothesis if z>1.28 mu = 920xbar = 910n = 30sigma = 25 The test statistic is given by z=x¯-μσn =910-9202530 =-2.19 Excel procedure: Conclusion: Here, the test statistic is less than the critical value. From the rejection rule, failed to reject the null hypothesis. It can be concluded that the mean sodium content in one of its breakfast sandwiches is no more than 920 milligrams.

Math

Statistics

A fast food restaurant estimates that the mean sodium content in one of its breakfast sandwiches is no more than 920 milligrams. A random sample of 30 breakfast sandwiches has a mean sodium content of 910 milligra population standard deviation is 25 milligrams. At a = 0.10, do you have enough evidence to reject the restaurant's claim? Complete parts (a) through (e). (a) Identify the null hypothesis and alternative hypothesis. Yc. Ho: us920 (claim) ΟΑ Η : μ5910 H:u<910 (claim) O B. Ho: H=910 (claim) H:u> 920 O E. Ho:u<910 (claim) O D. Ho: u>920 Ha:us 920 (claim) OF. Ho: u#920 (claim) H:p= 920 H: u2910 (b) Identify the critical value(s). Use technology. = 1.28 (Use a comma separate answers as needed. Round to two decimal places as needed.) Identify the rejection region(s). Select the correct choice below. The rejection region is z> 1.28. O B. The rejection region is z<1.28.

A fast food restaurant estimates that the mean sodium content in one of its breakfast sandwiches is no more than 920 milligrams. A random sample of 30 breakfast sandwiches has a mean sodium content of 910 milligra population standard deviation is 25 milligrams. At a = 0.10, do you have enough evidence to reject the restaurant's claim? Complete parts (a) through (e). (a) Identify the null hypothesis and alternative hypothesis. Yc. Ho: us920 (claim) ΟΑ Η : μ5910 H:u<910 (claim) O B. Ho: H=910 (claim) H:u> 920 O E. Ho:u<910 (claim) O D. Ho: u>920 Ha:us 920 (claim) OF. Ho: u#920 (claim) H:p= 920 H: u2910 (b) Identify the critical value(s). Use technology. = 1.28 (Use a comma separate answers as needed. Round to two decimal places as needed.) Identify the rejection region(s). Select the correct choice below. The rejection region is z> 1.28. O B. The rejection region is z<1.28.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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