A nutritionist claims that the mean tuna consumption by a person is 3.4 pounds per year. A sample of 80 people shows that the mean tuna consumption by a 3.3 pounds per year. Assume the population standard deviation is 1.24 pounds. At a = 0.08, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. O A. Ho: u#3.3 O B. Ho: H53.4 OC. Ho:u>3.4 Hg: = 3.3 Ha: u> 3.4 Hius3.4 OF. Ho: us3.3 H:p>3.3 O D. Ho: u>3.3 O E. Ho: H=3.4 Ha: us3.3 (b) Identify the standardized test statistic. (Round to two decimal places as needed.) (c) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Reject Ho. There is not sufficient evidence to reject the claim that mean O B. Reject Ho. There is sufficient evidence to reject the claim that mean tuna tuna consumption is equal to 3.4 pounds. consumption is equal to 3.4 pounds. O C. Fail to reject Ho. There is sufficient evidence to reject the claim that mean O D. Fail to reject Ho- There is not sufficient evidence to reject the claim that tuna consumption is equal to 3.4 pounds. mean tuna consumption is equal to 3.4 pounds.

For each of the examples below, go through the four steps of hypothesis testing; report your results in APA format. Use alpha of .05 and a two tailed test for each example.   According to 2014 data from the Centers for Disease Control and Prevention, the average life expectancy in the United States is 78.74 years with other sources listing the standard deviation, σ, for this data as 16.5 years. A researcher is interested in determining if rock musicians die at an earlier age and collects a random sample of 45 dead rock musicians. The researcher finds an average age of death of 45.2 years for the sample. Use this statistic to evaluate the researcher’s hypothesis.

A school district claims that the average salary of elementary school teachers in their district is more than the national average of $42,000. A sample of 30 elementary school teachers from that district have a mean salary $43,260. The standard deviation for the population is $5,230. At α = 0.05, test their claim that teachers in their district earn more than $42,000 per year.

The mean age of graduate students at a University is at most 31 years with a standard deviation of 2 years. A random sample of 15 graduate students is taken. The sample mean is 32 years and the sample standard deviation is 3 years. Are the data significant at the 1% level? a. State the null and alternative hypothesesb. Performzscore and find p-valuec. Perform Cohen's d equationd. State answer

A population has a mean μ = 73 and a standard deviation o = 28. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 257. Hx ox (Simplify your answer.) (Type an integer or decimal rounded to three decimal places as needed.)

The average dues paid by students at state universities across the country were $2236 per student last year. The average for a random sample of 500 students this year is $2350. Given the following hypotheses, Ho: 4 = 2236 (The average fees are the same as last year.) Ha: M + 2236 (The average fees are not the same as last year.) compute the p-value for the sample result. Assume the population standard deviation is $724. If the significance level is 5%, can the null hypothesis be rejected?

Calcium levels in people are normally distributed with a mean of 9.7 mgdL and a standard deviation of 0.5 mgdL . Individuals with calcium levels in the bottom 10% of the population are considered to have low calcium levels. Find the calcium level that is the borderline between low calcium levels and those not considered low. Carry your intermediate computations to at least four decimal places. Round your answer to one decimal place.

Assume that the heights of adult puffins are normally distributed, with a mean of μ=μ= 15.9 inches and a standard deviation of σ=σ= 2.7 inches.  For a random sample of 28 puffins, answer the following: What is the mean of the distribution of x¯ ?

The average income of 15 randomly selected families who reside in a large metropolitan East Coast city is $62,456. The standard deviation is $9652. The average income of 11 randomly selected families who reside in a rural area of the Midwest is $60,213, with a standard deviation of $2009. At α = 0.05, can it be concluded that the families who live in the cities have a higher income than those who live in the rural areas? Assume the population is normally distributed. Required steps: Step 1: Label all given information. Step 2:State the null and alternative hypothesis and identify the claim. Step 3:Verify that the conditions are met to perform the test. Step 4:Sketch the normal distribution and find the critical regions. Step 5:Compute the test statistic. Step 6:Make a decision Step 7:Summarize the results.

A nutritionist claims that the mean tuna consumption by a person is 3.8 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.5 pounds per year. Assume the population standard deviation is 1.04 pounds. At α=0.09​, can you reject the​ claim?     ​(a) Identify the null hypothesis and alternative hypothesis.     A. H0​: μ=3.8 Ha​: μ≠3.8   B. H0​: μ≠3.5 Ha​: μ=3.5   C. H0​: μ>3.5 Ha​: μ≤3.5   D. H0​: μ>3.8 Ha​: μ≤3.8   E. H0​: μ≤3.5 Ha​: μ>3.5   F. H0​: μ≤3.8 Ha​:μ>3.8   b) Identify the standardized test statistic. z= ​(Round to two decimal places as​ needed.)   (c) Find the​ P-value.   (d) Decide whether to reject or fail to reject the null hypothesis.     A. Reject H0. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8pounds.   B. Reject H0. There is sufficient evidence to reject the claim that mean tuna consumption is equal to…