A falling package with a parachute is greatly affected by air resistance. Suppose a package (m 25 kg), dropped from an altitude of y = 1500 m, hits the ground at a speed of v = 45 m/s. Calculate the work done by air resistance. By conservation of energy, the initial total mechanical energy is equal to the final total mechanical energy. Let K be the kinetic energy, U be the gravitational potential energy, and Wair be the work done by the drag force from air resistance.

A falling package with a parachute is greatly affected by air resistance. Suppose a package (m 25 kg), dropped from an altitude of y = 1500 m, hits the ground at a speed of v = 45 m/s. Calculate the work done by air resistance. By conservation of energy, the initial total mechanical energy is equal to the final total mechanical energy. Let K be the kinetic energy, U be the gravitational potential energy, and Wair be the work done by the drag force from air resistance.

Name: E1 = E2K1 + U1 + Wair = K2 + U2Some of the terms in the equation abov
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Description: E1 = E2K1 + U1 + Wair = K2 + U2Some of the terms in the equation above are zero so it can be simplified to:+ Wair =Isolating the work done by air resistance, we get:Wair = ½- mPlugging in the values given, the work done by air resistance is:Wair =2.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A falling package with a parachute is greatly affected by air resistance. Suppose a package (m = 25 kg), dropped from an altitude of y = 1500 m, hits the ground at a speed of v = 45 m/s. Calculate the work done by air resistance. By conservation of energy, the initial total mechanical energy is equal to the final total mechanical energy. Let K be the kinetic energy, U be the gravitational potential energy, and Wair be the work done by the drag force from air resistance. E1 = E2 K1 + U1 + Wair = K2 + U2 Some of the terms in the equation above are zero so it can be simplified to: + Wair = Isolating the work done by air resistance, we get: Wair = ½ - m Plugging in the values given, the work done by air resistance is: Wair = 2.19 kJ kindly box the answer so that I won't be confused, Thank you!!!
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