Elements Of Electromagnetics
7th Edition
ISBN: 9780190698614
Author: Sadiku, Matthew N. O.
Publisher: Oxford University Press
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- For the beam shown, the magnitude of the distributed load is wo = 11.8 kN/m and the beam length is L = 7.9 m. (a) derive equations for the shear force Vand the bending moment M for any location in the beam. Place the origin at point A. (b) use the derived functions to plot the shear-force and bending-moment diagrams for the beam. Use your diagrams to determine the maximum shear force and maximum bending moment. Note that answers may be positive or negative. Here, "maximum" refers to the largest magnitude value, but you should enter your shear force and bending moment with the correct sign, using the sign convention presented in Section 7.2 of the textbook. If the magnitudes of the largest positive and largest negative values are the same, enter a positive number. Wo A В L. Answer: Vmax = kN Mmax kN•marrow_forwardplease don't copy itarrow_forwardA cantilevered beam is loaded with a uniformly distributed load as shown below. If w1 = 2000 lb/ft, what is the value of the moment (ft-lb) at x = 2 ft?(NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE)arrow_forward
- Determine the maximum positive normal bending stress that occurs in member ABC of the engine crane given the following information: Engine weight = 1500 lb Member ABC height (vertical cross sectional dimension) = 7 in Member ABC width (horizontal cross sectional dimension) = 1 in Express your answer to the nearest whole psi value. In your work, draw the shear and moment diagram for member ABC. For the question above, determine the maximum shear stress in member ABC that occurs between points A and B. Express your answer using the nearest whole psi value.arrow_forwardA simply supported beam is loaded as shown below. The distributed load has a constant value in the first region with a value of w = 18 kN/m. In the second region, the distributed load linearly decreases from 18 kN/m to 10 kN/m. In the third region, the distributed load has a constant value of v = 10 kN/m. What is the moment generated by the distributed load about point A in kN-m? 1m film W A 1m 1m V Barrow_forwardI keep getting stuck on the moment diagram for this problem. How do I solve it?arrow_forward
- please draw a shear diagram and a moment diagram No elements selected 150 lb-ft V, lb 3000 2500 2000 1500 1000 500 0 0 -500 -1000 -1500- -2000 -2500 -3000 250 lb/h 20 ft 10 20 150 lb-ft z, ftarrow_forwardEstablish the Shear & Moment Equation and Diagram of the loaded beam shown. Consider the Left Body Diagram of each section in establishing the equations. Draw and label the figure properly. Locate the maximum moment and the point of inflection. Figure: 5 kN/m 5 m 12 kN 50 kN-m n D B 2.5m C 2.5 marrow_forwardA fixed beam of length 3 m is subjected to the distributed load shown above. (A) state the reaction forces at A and C (B) Write the equations for bending moment and shear force at any section along the beam and draw the shear force and bending moment diagram. (C) State the maximal bending moment and shear force and their locations.arrow_forward
- QUESTION 1 Determine the reaction moment at x = 0 in kN-m. QUESTION 2 Determine the vertical reaction force at x = 0 in kN. QUESTION 3 (1-3) Determine the horizontal reaction force at x = 0 in kN. The distributed load, f(x), is equal to 100 kN/m. /// f(x) 3 marrow_forwardDetermine the shear and moment equations for the beam shown in the figure. Also, draw the shear and moment diagrams, specifying values at all change of loading positions and at all section of zero shear.arrow_forwardAn extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 620 mm. The cross-sectional dimensions of the beam are b₁ = 39 mm, d₁ = 94 mm, b₂ = 23 mm, d₂ = 23 mm, and a = 8 mm. For this material, the allowable tensile bending stress is 17 MPa, and the allowable compressive bending stress is 11 MPa. Determine the largest moment M that can be applied as shown to the beam. ak a ↓ a M B A Answer: M = i L N•m b₁arrow_forward
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