A diverging lens always produces a virtual erect image. A diverging lens always produces a virtual inverted image. A diverging lens produces a virtual erect image only if the object is located within the focal point of the lens.

A person looks at a gem using a converging lens with a focal length of 13.8 cm. The lens forms a virtual image 33.1 cm from the lens. Find the magnification. Describe the image. 1. real, upright, larger 2. real, inverted, larger 3. virtual, upright, larger 4. real, inverted, smaller 5. virtual, inverted, larger 6. real, upright, smaller 7. virtual, inverted, smaller 8. virtual, upright, smaller

Famous jeweler Gabi Tolkowsky is looking at a 3.0-cm-tall perfect oval-shaped diamond through a thin lens. The diamond is 20.0 cm behind the lens, and the distance between its upright image and the lens is 40.0 cm. What is the focal length of the lens? Is it converging or diverging? How tall is the image? 
 PLEASE PLEASE draw a ray diagram and define variables

In the following three scenarios, an object is located on one side of a converging lens. In each case, you must determine if the lens forms an image of this object. If it does, you also must determine the following. whether the image is real or virtual whether the image is upright or inverted the image's location, q the image's magnification, M The focal length is  f = 13.0 cm  for this lens. Set both q and M to zero if no image exists. Note: If q appears to be infinite, the image does not exist (but nevertheless set q to 0 when entering your answers to that particular scenario).   (a) The object lies at position 13.0 cm. (Enter the value for q in cm.) q=? M=?   Select all that apply to part (a). real, virtual, upright, inverted, no image   (b) The object lies at position 1.44 cm. (Enter the value for q in cm.) q=? M=?   Select all that apply to part (b). real, virtual, upright, inverted, no image   (c) The object lies at position 71.5 cm. (Enter the value for q in cm.) q=?…

You are having trouble reading your cheat sheet during your physics exam because you wrote so small. You foresaw the problem, so you brought a small lens with you to the exam. You hold the lens 6 cm away from the page. The image you see is upright and 2.9 times the size of the writing on the page. where is image formed  Is the image real or virtual  what is the focal length of the lens  are you using a converting lens or a diverging lens

Q: You hold up a piece of paper by a lens and see the image of a candle projected on the paper. Is this image real or virtual? Q: Will the projected image show the candle right-side-up or upside-down? Q: You look through a concave (diverging) lens at a candle. Will the image you see be smaller or larger in size than the actual candle?

A small object is placed to the left of a convex lens and on its optical axis. The object is 46 cm from the lens, which has a focal length of 15 cm.Determine the location of the image formed by the lens. (Enter your answer in cm from the lens.) 1. cm from the lens 2. Describe the image.

A contact lens is made of plastic with an index of refraction of 1.5. The lens has an outer radius of curvature of +2 cm and an inner radius of curvature of +2.5 cm. a) What is its focal length? b) If we place an object at a distance of 5 cm from this lens, what will be the distance between the object and its image? draw the diagram