A dielectric with a constant k = 4 and a thickness of b = 2 mm is inserted into a parallel strip capacitor having a surface area of A = 2.40 cm2 and a spacing of d = 4 mm as shown in the figure. The dielectric is placed right in the middle of the two pieces, the rest is filled with air. Specify: a. The equivalent capacitance of the capacitor after inserting the dielectric b. The ratio between the energy stored in the capacitor before and after insertion of the dielectric if given a potential difference of 10 V.

A capacitor of 3.23µF has an area of 6.35mm^2. Determine the separation distance between the two plates. If the new capacitance is now 5.63mF, what is the value of the dielectric inserted to the capacitor? What is the new voltage if the capacitor is connected to a 110 volts source? If the electric field created by two plates 8.99x10^4 N/C and a working voltage of 63 volts. Will the capacitor experience a dielectric breakdown? Please prove your answer. Note: This question is under the topic "Capacitance". Thank you!

Regarding the Earth and a cloud layer 800 m above the Earth as the "plates" of a capacitor, calculate the capacitance. Assume the cloud layer has an area of 1 km2 and that the air between the cloud and the ground is pure and dry. nF   Assume charge builds up on the cloud and on the ground until a uniform electric field of 2.0 106 N/C throughout the space between them makes the air break down and conduct electricity as a lightning bolt. What is the maximum charge the cloud can hold? C