A capacitor of 3.23µF has an area of 6.35mm^2. Determine the separation distance between the two plates. If the new capacitance is now 5.63mF, what is the value of the dielectric inserted to the capacitor? What is the new voltage if the capacitor is connected to a 110 volts source? If the electric field created by two plates 8.99x10^4 N/C and a working voltage of 63 volts. Will the capacitor experience a dielectric breakdown? Please prove your answer.

In Lab 3, we measured the dielectric constant of glass using a parallel plate capacitor. Suppose that a piece of flat glass panel with a linear dielectric constant ɛ, = 2.5 is inserted between the plates of such a capacitor. The thickness of the glass is d = 5mm. The glass is in contact with both plates. One of the plates of the capacitor is kept at +3V, and the other plate is grounded. Treat the plates as infinitely large and thus the electric field is uniform between the plates. a) Calculate the electric field between the plates. b) Calculate the (uniform) polarization created in the glass. c) Calculate the surface bound charge density on the side of the glass that is in contact with the positive plate of the capacitor. d) Calculate the electric displacement between the plates. e) Calculate the free charge per unit area on the positive plate of the capacitor.

Two 2.10 cm x 2.10 cm plates that form a parallel- plate capacitor are charged to ±0.708 nC. ▾ Part A What is the electric field strength inside the capacitor if the spacing between the plates is 1.30 mm? Express your answer with the appropriate units. E= Value Submit Request Answer Part B ? Units What is potential difference across the capacitor if the spacing between the plates is 1.30 mm ? Express your answer with the appropriate units. HÅ V = Value Units Submit Request Answer Part C ? What is the electric field strength inside the capacitor if the spacing between the plates is 2.60 mm ? Express your answer with the appropriate units. με E = Value Units Submit Request Answer Part D ? What is the potential difference across the capacitor if the spacing between the plates is 2.60 mm ? Express your answer with the appropriate units. ΜΑ ? V = Value Units Submit Request Answer Provide Feedback

A parallel-plate capacitor is made of two square plates 20 cm on a side and 1 mm apart. The capacitor is connected to a 50-V battery. Hint # a. What is the energy stored in the capacitor? Energy stored in the capacitor is b. With the battery still connected, the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? Energy now stored in the capacitor is c. This time, starting from situation in (a), with the batteries disconnected (but capacitors still charged), the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? Energy now stored in the capacitor is d. Comparing your results in (b) and (c) above, it makes sense that the energy stored in the capacitor- increases in (c), because the work done in separating the plates is stored as the electrostatic potential energy. In (b), why does the energy decrease even though work is done in separating the plates? E D Submit Question с 4 O The energy is not…