A day on Splorg lasts the equivalent of 31.7 hours. At the equator, Splorg has a circumference of 54,660 km. It takes a 2 kg mass exactly 0.56 s to fall a distance of 2 m at the surface of Splorg. At what radial distance would you need to orbit a satellite so that it always remained at the same location above the Splorigian equator (i.e. in splorgeosynchronous orbit)? At what velocity does the spacecraft need to reach in order for it to escape the gravity of Splorg.

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