
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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A correct expression for Henderson-Hasselbalch equation for the acidic buffer HA/A- is:
Group of answer choices
pH = pKa+ log{[A-]/[HA]
pH = 14 - pOH
pH = -log[H3O+]
pH = pKa- log{[A-]/[HA]
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- Design a buffer that has a pH of 4.66 using one of the weak acid/conjugate base systems shown below. Weak Acid Conjugate Base Ka pKa HC2O4- C2O42- 6.4 × 10-5 4.19 H2PO4- HPO42- 6.2 × 10-8 7.21 HCO3- CO32- 4.8 × 10-11 10.32 How many grams of the potassium salt of the weak acid must be combined with how many grams of the potassium salt of its conjugate base, to produce 1.00 L of a buffer that is 1.00 M in the weak base?grams potassium salt of weak acid = grams potassium salt of conjugate base =arrow_forwardWe add 10mL of 0.1M NaOH to 100mL of 0.1M CH3COOH/ 0.1M CH3COO^-. (Ka = 1.8 x10 ^-5). Using the Henderson-Hasselbach equation, pH=pKa + log [A-]/[HA] a) before the addition of NaOH b) after the addition of NaOHarrow_forwardQ4arrow_forward
- What is the pH of the buffer that results when 2.3 g of NH3 and 6.46 g of NH4Cl are dissolved in 250 mL water? (Ka for NH4+ = 5.60 × 10-10) Please give the answer to 2 decimal places.arrow_forwardDesign a buffer that has a pH of 6.70 using one of the weak acid/conjugate base systems shown below. Weak Acid Conjugate Base Ką pKa HC,04 C,0,²- 6.4 x 10-5 4.19 H,PO4 HPO,2- 6.2 x 10-8 7.21 HCO3 co,?- 4.8 × 10-11| 10.32 How many grams of the potassium salt of the weak acid must be combined with how many grams of the potassium salt of its conjugate base, to produce 1.00 L of a buffer that is 1.00 M in the weak base? grams potassium salt of weak acid = grams potassium salt of conjugate base =arrow_forwardA student needs to prepare a buffer made from HNO2 and NaNO2 with pH 3.655. If Ka for HNO2 is 4.50 x 10^-4, what ratio of [HNO2]/[NO2-] is required?arrow_forward
- Assuming equal concentrations of conjugate base and acid, which one of the following mixtures is best suited for preparing a buffer solution with pH of 4.74? Question 2 options: NH3 / NH4Cl (Ka = 5.6 × 10–10) NaNO2 / HNO2 (Ka = 4.5 × 10–4) CH3COONa / CH3COOH (Ka = 1.8 × 10–5) NaCl / HCl NaOCl / HOCl (Ka = 3.2 × 10–8)arrow_forwardA student needs to prepare a buffer solution with a pH of 4.18. Assuming a pKa of 4.69, how many mL of 0.1 M NaOH would need to be added to 15.0 mL of 0.1 M HB to prepare this buffer? Please include a proper (abbreviated) unit. HINT : Use pH = pKa + log ([B minus]/[HB]) or, if concentrations are the same, pH = pKa + log (Volume of OH minus/ (Volume of HB minus Volume of OH minus)arrow_forwardWhich is true about buffer solutions? -they hold the pH close to the pKa -they contain comparable moles of a weak acid and a strong base - they hold pH constant at pH=7 -they prevent acids and bases from reaching equilibrium -they hold the pH close to the equivalence point pHarrow_forward
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