A conductor suspended by two flexible wires has a mass per unit length of 0.04 kg/m as shown in Figure 3. Determine the magnitude and direction of the current that must exist in the conductor in order for the tension in the supporting wires to be zero when the magnetic field is 3.6 T into the page. The force due to weight of the conductor is given as W = mg. x Bin

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Chapter1: Units, Trigonometry. And Vectors
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A conductor suspended by two flexible wires has a mass per unit length of 0.04 kg/m as shown
in Figure 3. Determine the magnitude and direction of the current that must exist in the
conductor in order for the tension in the supporting wires to be zero when the magnetic field is
3.6 T into the page. The force due to weight of the conductor is given as W = mg.
x Bịn
Figure 3
Page 1 of 1
73 words
E English (Malaysia)
D. Focus
100%
10:13 AM
CS
A 56 G
W
02/02/2021
Transcribed Image Text:AutoSave Off Document1 - Word O Search retroget R File Home Insert Design Layout References Mailings Review View Help A Share P Comments X Cut -A A Aa E -E - E- EE T P Find - AaBbCcDc AaBbCcDc AaBbC AaBbCcC AaB I No Spac. Heading 1 Heading 2 Calibri (Body) v 11 - Ap BCopy Paste Replace Dictate Sensitivity BIU - ab x, x A - I- A v 三 三。 、H I Normal Title S Format Painter A Select Clipboard Font Paragraph Styles Editing Voice Sensitivity A conductor suspended by two flexible wires has a mass per unit length of 0.04 kg/m as shown in Figure 3. Determine the magnitude and direction of the current that must exist in the conductor in order for the tension in the supporting wires to be zero when the magnetic field is 3.6 T into the page. The force due to weight of the conductor is given as W = mg. x Bịn Figure 3 Page 1 of 1 73 words E English (Malaysia) D. Focus 100% 10:13 AM CS A 56 G W 02/02/2021
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