A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 132.2-cm and a standard deviation of 1.4-cm. Find the probability that the length of a randomly selected steel rod is between 131.4-cm and 135.6-cm. P(131.4-cm < X < 135.6-cm) =  Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

A soft drink machine outputs a mean of 29 ounces per cup. The machine's output is normally distributed with a standard deviation of 4 ounces. What is the probability of filling a cup between 25 and 31 ounces? Round your answer to four decimal places. Answer esc If you would like to look up the value in a table, select the table you want to view, then either click the cell at the intersection of the row and column or use the arrow keys to find the appropriate cell in the table and select it using the Space key. angle. 9 ! 1 9 a Z ← @ 2 W S X # 3 e d C C $ 4 r f % 5 V t Oll A 6 Normal Table - to-z Normal Table - to z b y h & 7 n O u * 8 3 O i N ( 9 k O < 1 alt ) 0 1 Р O - : Tables ; Submit Answer 4 ? 1 + = Keypad Keyboard Shortcuts 31 11 1 Oct 28 }. backspace 1 USE YOUR SMARTPHONE FOR 2:53 3 D45 enter

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 217.3-cm and a standard deviation of 2.3-cm. For shipment, 15 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 216.2. cm and 218.9-cm. P(216.2-cm < M 218.9-cm) - Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z- scores rounded to 3 decimal places are accepted. Submit Question 4

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 225.1-cm and a standard deviation of 1.4-cm. For shipment, 12 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 224.1-cm and 224.6-cm. P(224.1-cm < M < 224.6-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 258.1 cm and a standard deviation of 0.5 cm. For shipment, 14 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 257.8 cm and 258.4 cm.P(257.8 cm < x¯ < 258.4 cm) = Enter your answer as a number accurate to 4 decimal places. Answers should be obtained using z-scores correct to two decimal places.

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 226-cm and a standard deviation of 1.1-cm. For shipment, 28 steel rods are bundled together.Find P58, which is the average length separating the smallest 58% bundles from the largest 42% bundles.P58 = -cmEnter your answer as a number accurate to 2 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

A manufacturer of phone batteries determines that the average length of talk time for one of its batteries is 470 minutes.  Suppose that the standard deviation is known to be 32 minutes and that the data are approximately bell-shaped. Estimate the percentage of batteries whose talk time is between 406 minutes and 534 minutes. Estimate the percentage of batteries whose talk time is less than 438 minutes. Estimate the percentage of batteries whose talk time is more than 534 minutes. answer in excel

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 119.5-cm and a standard deviation of 2.2-cm. For shipment, 24 steel rods are bundled together.Find P75, which is the average length separating the smallest 75% bundles from the largest 25% bundles.P75 = -cm

A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 122.7-cm and a standard deviation of 0.5-cm.Find P15, which is the length separating the shortest 15% rods from the longest 85%.P15 = -cm