MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- The total annual precipitation for a region is approximately normallydistributed with a mean of 1050 mm and a standard deviation of 400 mm. What isthe probability of an annual precipitation greater than 1050 mm but less than 1300? Answer = 19.5arrow_forwardA company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 99.3-cm and a standard deviation of 1.5-cm. For shipment, 25 steel rods are bundled together.Find P27, which is the average length separating the smallest 27% bundles from the largest 73% bundles. P27 =arrow_forwardA company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 217.3-cm and a standard deviation of 2.3-cm. For shipment, 15 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 216.2. cm and 218.9-cm. P(216.2-cm < M 218.9-cm) - Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z- scores rounded to 3 decimal places are accepted. Submit Question 4arrow_forward
- A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 225.1-cm and a standard deviation of 1.4-cm. For shipment, 12 steel rods are bundled together.Find the probability that the average length of a randomly selected bundle of steel rods is between 224.1-cm and 224.6-cm. P(224.1-cm < M < 224.6-cm) = Enter your answer as a number accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.arrow_forwardA particular fruit's weights are normally distributed, with a mean of 455 grams and a standard deviation of 31 grams. If you pick 19 fruit at random, what is the probability that their mean weight will be between 434 grams and 443 grams? Use GeoGebra. Round to 4 places.arrow_forwardThe strength of the welds in a new manufacturing process is measured by the amount of weight needed to break the weld. The strength of the welds is normally distributed with mean 583 pounds. 30% of the welds had strength less than 500 pounds. What is the standard deviation of the strength of the welds?arrow_forward
- The mean weight of a Great Dane is 63.0 kg with a standard deviation of 2.3 kg. Suppose a researcher randomly samples 61 Great Danes and records the weights of the sampled dogs. Calculate the standard deviation of the mean, rounded to 2 decimal placesarrow_forwardA manufacturer of phone batteries determines that the average length of talk time for one of its batteries is 470 minutes. Suppose that the standard deviation is known to be 32 minutes and that the data are approximately bell-shaped. Estimate the percentage of batteries whose talk time is between 406 minutes and 534 minutes. Estimate the percentage of batteries whose talk time is less than 438 minutes. Estimate the percentage of batteries whose talk time is more than 534 minutes. answer in excelarrow_forwardResearchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.2 Mbps. The complete list of 50 data speeds has a mean of x= 15.49 Mbps and a standard deviation of s = 18.83Mbps.arrow_forward
- A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 157-cm and a standard deviation of 0.9-cm. For shipment, 5 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 156-cm and 157.2-cm.P(156-cm < M < 157.2-cm)arrow_forwardA company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 119.5-cm and a standard deviation of 2.2-cm. For shipment, 24 steel rods are bundled together.Find P75, which is the average length separating the smallest 75% bundles from the largest 25% bundles.P75 = -cmarrow_forwardA company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 122.7-cm and a standard deviation of 0.5-cm.Find P15, which is the length separating the shortest 15% rods from the longest 85%.P15 = -cmarrow_forward
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