A closed cylindrical tank filled with water has a hemispherical dome and is connected to an inverted piping system as shown in the figure below. The liquid in the top part of the piping system has a specific gravity of 0.8, and the remaining parts of the system are filled with water. If the pressure gage reading at point A is 60 kPa, determine (a) the pressure in the pipe at B, and (b) the pressure head, in millimeters of mercury, at point C.

The pressure in a natural gas pipeline is measured by the manometer shown in the figure with one of the arms open to the atmosphere where the local atmospheric pressure is 14.2 psia. Determine the absolute pressure at the bottom of the natural gas pipeline. Take the height of the mercury column / to be 6 in. Take the density of water to be pw= 62.4 lbm/ft³, and the specific gravity of mercury to be 13.6 and its density is pHg = 848.6 lbm/ft3 (Natural) Gas 14 in -Mercury SG = 13.6 -Air 2 in 22 in -Water The absolute pressure at the bottom of the natural gas pipeline is psia.

Determine the height of the mercury in the tube if the level of water in the tube is h = 0.3m and the depths of the oil and water in the tank are 0.6 and 0.5 m, respectively as shown in Figure Q5. Take po = 900 kg/m³, pw = 1000 kg/m³, and PHg= 13550 kg/m³. 0.6 m 0.5 m B h'=0.3 m

The tank is filled with water and gasoline at a temperature of 20∘C to the depths shown in (Figure 1). The absolute air pressure at the top of the tank is 140 kPa. The atmospheric pressure is 101 kPa. Determine the gage pressue at the bottom of the tank. Also would the results be different if the tank had a flat bottom rather than a curved one?