A charged particle moving through a magnetic field at right angles to the field with a speed of 27.7 m/s experiences a magnetic force of 2.98e-4N. Determine the magnetic force on an identical particle when it travel through the same magnetic field with a speed of 4.14 m/a at an angle of 28.2 degrees relative to the magnetic field

A cyclotron is a device for accelerating charged particles to high speed as they follow an expanding spiral-like path (See LHC, NSRRC, or an MRI machine). The charged particles are subjected to both an electric field and a magnetic field. One of these fields increases the speed of the charged particles, and the other field causes them to follow a curved path. Which one does the latter? The magnetic field, since it exerts a force to the moving charge perpendicular to the charges' direction of motion. The electric field, since it exerts a force that accelerates the particle in the curved path of the facility. Not necessarily only one. Both contributes to the particles' curving of path as both exert force perpendicular to their velocity's direction. None of them. The curving of charges occur due to the design of the facility/device.

Part 2) A proton moving with a speed 3.84 × 10° m/s through a 2.99 T magnetic field experiences a force of magnitude 1.59 x 10-12 N. (Mass of the proton = 1.673 × 10¬27 kg, charge 1.602 × 10-19 C). What is the angle between the proton's velocity and the magnetic field? Part 3) What is the proton's acceleration? a = m/s?

A charged particle moving through a magnetic field at right angles to the field with a speed of 30.7 m/s experiences a magnetic force of 2.98 x 10-4 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 4.84 m/s at an angle of 32.2° relative to the magnetic field.

A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 2.15 × 10-3 N. If this same charge were to move at the same speed and the angle between its velocity and the same magnetic field were 26.0o, what would be the magnitude of the magnetic force that the charge would experience?

An electron travelling at 5 x 106 m/s at right angles to a magnetic field experiences a magnetic force of 2 x 10–14 N. What is the strength of the magnetic field?.

When a charged particle moves perpendicularly to the direction of a uniform magnetic field, the direction of the magnetic force is perpendicular to both the direction of the magnetic field and the direction of the velocity of the charged particle.  Accordingly, the charge begins to move in a circular path.  Since the direction of the magnetic force is toward the center of the circular path the charged particle moves along, the magnetic force is a centripetal force (recall centripetal forces from chapter 5 of the text, covered in PHY 2010).  A schematic of such motion is shown below.  The "X"s represent the magnetic field that is directed into the plane of this screen.  The direction of velocity and magnetic force lie within the plane of this screen and are at right angles to one another, as shown below.   If a charge of magnitude 7.45x10-17C, with speed 4.66x106 m/s, and mass 7.12x10-25kg moves within the magnetic field of magnitude 3.96x10-2T, what is the resulting radius of the path…

A particle that has an 8.6-μC charge moves with a velocity of magnitude 4.8 × 105 m/s along the +x axis. The maximum possible magnetic force that the charge with the given speed could experience has a magnitude of 0.577 N. Find the magnitude of the magnetic field