A charged particle is moving in a uniform, constant magnetic field. Which one of the following statements concerning the magnetic force exerted on the particle is false?   Question 19 options:   It does no work on the particle.   It increases the speed of the particle.    It changes the velocity of the particle.    It can act only on a particle in motion.   It does not change the kinetic energy of the particle

A proton traveling at 24.7° with respect to the direction of a magnetic field of strength 2.33 mT experiences a magnetic force of 6.38 × 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts.

A proton traveling at 17.8° with respect to the direction of a magnetic field of strength 3.75 mT experiences a magnetic force of 6.19 x 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts. (a) Number i (b) Number i Units Units

A proton traveling at 26.4° with respect to the direction of a magnetic field of strength 2.15 mT experiences a magnetic force of 8.13 × 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts.

An electron with a kinetic energy of 1.04 x 104 eV is initially moving south in a uniform magnetic field of magnitude 488 G, directed east. Describe in detail the electron's trajectory, including its shape and orientation. the radius of the path   direction of initial force        shape of trajectory

#Q06

A charged particle, after entering a constant magnetic field B, starts moving freely along a circular path in the magnetic field applied perpendicular to the particle’s velocity (v).  What do you conclude about the particle’s kinetic energy (KE)? Group of answer choices KE remains unaltered as v and FB are perpendicular to each other KE increases under the constant magnetic force FB. KE decreases when magnetic force (FB) is perpendicular to the motion (v). KE and magnetic force FB are not correlated.

A charged particle moving through a magnetic field at right angles to the field with a speed of 30.7 m/s experiences a magnetic force of 2.98 x 10-4 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 4.84 m/s at an angle of 32.2° relative to the magnetic field.

An electron moves at a velocity of 3.05 x 10^6 m/s in a direction perpendicular to a magnetic field of strength 4.89 T. How much force will the electron experience? 4.06E-12 N 2.39E-12 N 1.43E-12 N 3.11E-12 N

Chapter 28, Problem 001 A proton traveling at 23.8° with respect to the direction of a magnetic field of strength 1.98 mT experiences a magnetic force of 9.59 × 10-¹7 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron- volts. Chapter 28, Problem 009 In the figure, an electron accelerated from rest through potential difference V₁=1.06 kV enters the gap between two parallel plates having separation d = 24.5 mm and potential difference V₂= 99.1 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? [₁}v₂