A certain reaction is known to have an activation energy E=42.0 kJ/mol. Furthermore, the rate of this r measured at 274. K and found to be 9.8M/s. Use this information to answer the questions in the table be Suppose the concentrations of all reactants is kept the same, but the temperature is raised by 5% from 274. K to 288. K. How will the rate of the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is added, which has the effect of lowering the activation energy by 10%, from 42.0 kJ/mol to 37.8 kJ/mol. How will the rate of the reaction change? The rate will The rate will ✓ choose one stay the same rise about 5% rise more than 5% rise less than 5% fall about 5% fall more than 5% fall less than 5% X

Some measurements of the initial rate of a certain reaction are given in the table below. [N:] H2 initial rate of reaction 0.355M 2.28M 17.0M/s 0.355M 0.704M 1.62M/s 0.0958M 2.28M 4.59M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbol. rate = k|| x10 k =

O KINETICS AND EQUILIBRIUM Deducing a rate law from initial reaction rate data Some measurements of the initial rate of a certain reaction are given in the table below. H, I, initial rate of reaction 0.735 M 0.260 M 78.0M/s 0.735 M 0.341 M 102. M/s 0.354 M 0.260 M 37.6M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbol. Do rate = k| x10 k = Explanation Check © 2021 McGraw-Hill Educat II

Deducing a rate law from initial reaction rate data Some measurements of the initial rate of a certain reaction are given in the table below. [N] [H] initial rate of reaction 0.335 M 2.47M 18.0M/s 0.335 M0.592M 1.03 M/s olo 0.521 M 2.47M 28.0 M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbol. rate = k|| Ix10 k = ||

The activation energy of the forward reaction 96.27 kJ/mol and the activation energy for the reverse reaction is 60.33 kJ/mol. What is the DH of the reaction?  78.3 kJ/mol    17.97 kJ/mol  -156.6 kJ/mol  35.94 kJ/mol

A certain catalyzed reaction is Known to have an activation energy Ea=29.0 kJ/mol. Furthermore, the rate of this reaction is measured at 331 K and found to be 2.7× 10* M/s. Use this information to answer the questions in the table below. Suppose the concentrations of all reactants is kept the same, but the temperature is raised by 10% from 331 K to 364 K. How will the rate or the reaction change? Suppose the concentrations of all reactants is kept the same, but the catalyst is removed which has the eftect of raising the activation energy by 10%, from 29.0 kJ/mol to 31.9 kJ mol How will the rate or the reaction change?

Some measurements of the initial rate of a certain reaction are given in the table below. [₂] [H₂] initial rate of reaction 2.38M 1.39 M 0.140 M/s 10.8M 1.39 M 2.88 M/s 2.38 M 0.584 M 0.0588 M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 3 significant digits. Also be sure your answer has the correct unit symbo rate = k ロ・ロ -0 Ś ? Continue k = X

Some measurements of the initial rate of a certain reaction are given in the table below. [N] [H] initial rate of reaction 0.957 M 2.07M 0.296 M/s 0.241 M 2.07M 0.0188 M/s 0.957 M 4.24M 0.606 M/s Use this information to write a rate law for this reaction, and calculate the value of the rate constant k. Round your value for the rate constant to 2 significant digits. Also be sure your answer has the correct unit symbol. rate= k = ☐ x10 On ロ・ロ ☐ G