Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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A cement lined rectangular channel 6m wide carries water at the rate of 30m3/s. Find the value of Manning’s constant, if the slope required to maintain a depth of 1.5m is 0.001242.
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- A 6-m-wide rectangular irrigation channel carries a discharge of 20.0 m3/sec. The channel has aslope of 0.02 and a Manning’s coefficient is n = 0.01. Determine the normal depth. Use both thefull expression of the hydraulic radius and the wide channel approximation. a) Assume wide channel and compute the normal depth as the slope decreases from 0.02down to 0.002 at increments of 0.002. Compute also the corresponding water speed.Plot the normal depth as function of the slope. b) Assume wide channel and compute the normal depth as the Manning’s coefficientincreases to 0.1 at increments of 0.01. Compute the corresponding water speed. Plot thenormal depth as function of the Manning’s coefficient.arrow_forwardwater flows at 12m^/s in a concrete trapezoidal channel n=0.015 bottom width 4m side slopes 2H:1V longitudinal slope = 0.0009.if the depth flow at a gauging station is measured as 0.8m use the direct step method to find the location where the depth is 1.0marrow_forwardA concrete gravity dam has the following data: Maximum water level = 300.00 m Bed level = 220.00 m R.L top of dam = 304.00 m %3D The d/s slope of 0.67:1 starts at RL of 295.00 m U/s face is vertical. Center line of the drainage gallery = 8.0 m from u/s face. Consider only weight of dam, water pressure and uplift pressure. Calculate only the normal stresses at the toe and heel of the dam, assuming 100% uplift pressure at the h eel and 50% at the gallery and zero at the toe.arrow_forward
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