A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass spectrometer and hits a detector at a point 10.0 cm to the left of where the beam leaves the velocity selector. The velocity selector and the detector are both in a region of magentic field of strength 0.500 T. What is the speed of the particle after it leaves the velocity selecctor? Then, what is the accelerating potential needed to reach the speed found in that part if the ions start from rest?

University Physics Volume 2
18th Edition
ISBN:9781938168161
Author:OpenStax
Publisher:OpenStax
Chapter12: Sources Of Magnetic Fields
Section: Chapter Questions
Problem 12.8CYU: Check your Understanding Repeat the calculations from the previous example for I0=0.040A .
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A carbon-14 ion with a charge of +6.408x10^-19 C and a mass of 2.34x10^-26 kg is sent through a mass spectrometer and hits a detector at a point 10.0 cm to the left of  where the beam leaves the velocity selector. The velocity selector and the detector are both in a region of magentic field of strength 0.500 T. 

 

What is the speed of the particle after it leaves the velocity selecctor? Then, what is the accelerating potential needed to reach the speed found in that part if the ions start from rest?

 

Please also explain and show the steps you used to get there/the physics behind why/how you got to the answer to help me better understand. Thank you soo much. Also, the work and the explanation or most important because I already have the correct answer - I'm just unsure of how to get there. 

Region of
uniform
Particle
path
magnetic field
10.0 cm
Accelerating
plates
B
detector
15.0 cm
Transcribed Image Text:Region of uniform Particle path magnetic field 10.0 cm Accelerating plates B detector 15.0 cm
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