A car A is travelling along a straight path, while a lorry B is travelling along a circular path having a radius of curvature of 200 m as shown in Figure Q3. At the instant shown, car A travel at the velocity of (150+X) km/h while lorry B travel at the velocity of 80 km/h. Also at this instant, car A has an increase velocity of 7000 km/h? and lorry B has a decrease velocity of 4500 km/h². The angle between straight path of car A and the horizontal line is 0=65°. (a) Calculate the magnitude and direction of velocity of lorry B with respect to car A. ([C3], , (b) Determine the magnitude and direction of acceleration of lorry B as measured by the driver of car A.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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the last digit of matrix number is: 008

A car A is travelling along a straight path, while a lorry B is travelling along a circular path
having a radius of curvature of 200 m as shown in Figure Q3. At the instant shown, car A
travel at the velocity of (150+X) km/h while lorry B travel at the velocity of 80 km/h. Also
at this instant, car A has an increase velocity of 7000 km/h² and lorry B has a decrease
velocity of 4500 km/h². The angle between straight path of car A and the horizontal line is
0=65°.
Q3
(a) Calculate the magnitude and direction of velocity of lorry B with respect to car A.
([C3], ,
(b) Determine the magnitude and direction of acceleration of lorry B as measured by the
driver of car A.
([C4], "
your matrix number by adding the last three digits to get the value of X on the velocity
of plane A. The value of X will then need to be added with the digit of 150 as follows;
Example; If your matrix number is AD190251,
Velocity of plane A, VA= 150 +X km/h
X= (2 + 5 + 1) = 8
Therefore, the velocity of plane A, VA = 150 + X, = 150 + 8 = 158 km/h.
Use
Activate Windows
Go to Settings to activate V
Transcribed Image Text:A car A is travelling along a straight path, while a lorry B is travelling along a circular path having a radius of curvature of 200 m as shown in Figure Q3. At the instant shown, car A travel at the velocity of (150+X) km/h while lorry B travel at the velocity of 80 km/h. Also at this instant, car A has an increase velocity of 7000 km/h² and lorry B has a decrease velocity of 4500 km/h². The angle between straight path of car A and the horizontal line is 0=65°. Q3 (a) Calculate the magnitude and direction of velocity of lorry B with respect to car A. ([C3], , (b) Determine the magnitude and direction of acceleration of lorry B as measured by the driver of car A. ([C4], " your matrix number by adding the last three digits to get the value of X on the velocity of plane A. The value of X will then need to be added with the digit of 150 as follows; Example; If your matrix number is AD190251, Velocity of plane A, VA= 150 +X km/h X= (2 + 5 + 1) = 8 Therefore, the velocity of plane A, VA = 150 + X, = 150 + 8 = 158 km/h. Use Activate Windows Go to Settings to activate V
A
v(150+ X)kmh
Vg- 80 km/h
65
a4 = 7000 km/ h?
B
ав — 4500 kmт/h?
Activate Windows
Figure Q3
Go to Settings to activate W.
Transcribed Image Text:A v(150+ X)kmh Vg- 80 km/h 65 a4 = 7000 km/ h? B ав — 4500 kmт/h? Activate Windows Figure Q3 Go to Settings to activate W.
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