A cannon ball is launched into the air with an upward velocity of 294 feet per second, from a 10-foot tall cannon. The height hh of the cannon ball after tt seconds can be found using the equation h=−16t2+294t+10h=-16t2+294t+10. A) What was the initial height of the cannon ball? feet B) How many seconds will it take for the cannon ball to hit the ground? seconds

A cannon ball is launched into the air with an upward velocity of 294 feet per second, from a 10-foot tall cannon. The height hh of the cannon ball after tt seconds can be found using the equation h=−16t2+294t+10h=-16t2+294t+10. A) What was the initial height of the cannon ball? feet B) How many seconds will it take for the cannon ball to hit the ground? seconds

Physics for Scientists and Engineers with Modern Physics

10th Edition

ISBN:9781337553292

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Vectors

Section: Chapter Questions

Problem 35AP: A person going for a walk follows the path shown in Figure P3.35. The total trip consists of four...

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