(a) Calculate the enthalpy change, ΔrH°, for the formation of 1.00 mol of strontium carbonate (the material that gives the red color in fireworks) from its elements. Sr(s) + C(s) + 3/2 O2(g) → SrCO3(s)The experimental information available isSr(s) +1/2 O2(g) → SrO(s)ΔfH°' = -592 kJ/mol-rxnSrO(s) + CO2(g) → SrCO3(s)ΔrH° = -234 kJ/mol-rxnC(graphite) + O2(g) → CO2(g)ΔfH° = -394 kJ/mol-rxn(b) Draw an energy level diagram relating the energy quantities in this problem.
(a) Calculate the enthalpy change, ΔrH°, for the formation of 1.00 mol of strontium carbonate (the material that gives the red color in fireworks) from its elements. Sr(s) + C(s) + 3/2 O2(g) → SrCO3(s)The experimental information available isSr(s) +1/2 O2(g) → SrO(s)ΔfH°' = -592 kJ/mol-rxnSrO(s) + CO2(g) → SrCO3(s)ΔrH° = -234 kJ/mol-rxnC(graphite) + O2(g) → CO2(g)ΔfH° = -394 kJ/mol-rxn(b) Draw an energy level diagram relating the energy quantities in this problem.
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.33QE: The enthalpy change for the following reaction is 393.5 kJ. C(s,graphite)+O2(g)CO2(g) (a) Is energy...
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(a) Calculate the enthalpy change, ΔrH°, for the formation of 1.00 mol of strontium carbonate (the material that gives the red color in fireworks) from its elements. Sr(s) + C(s) + 3/2 O2(g) → SrCO3(s)
The experimental information available is
Sr(s) +1/2 O2(g) → SrO(s)
ΔfH°' = -592 kJ/mol-rxn
SrO(s) + CO2(g) → SrCO3(s)
ΔrH° = -234 kJ/mol-rxn
C(graphite) + O2(g) → CO2(g)
ΔfH° = -394 kJ/mol-rxn
(b) Draw an energy level diagram relating the energy quantities in this problem.
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