a) Calculate the enantiomeric excess of the styrene epoxide to the nearest %. % b) There are some small peaks between 4 and 8 minutes. Are these more or less polar than the product styrene oxide?
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![The following chromatogram was generated when analysing an enantioenriched epoxide. The peaks at 12.387 and 12.779 correspond to the two
enantiomers of the styrene epoxide.
FID1 A, Front Signal
210-
200-
190-
180-
170-
160-
150
140-
130
120-
110-
100-
90-
80-
70-
60-
50-
40.
0
30
20
10-
6 o'5 i 15 Ź 25 3 35 4 45 5 55 6 6'5 † 75 8 85 9 95 10 10 5 11 11.5 12 12.5 13 13.5 14 14.5 15 15.5 1616.5
Time (min)
Signal:
FID1 A, Front Signal
RT [min] Type Width [min]
Area
Height
Area% Name
1.834 BB
0.0239
1.9402
1.2638
0.0156
1.941 BV S
0.0105
1157.4164
1794.9219
9.3066
1.997 BV T
0.0233
0.5005
0.3021
0.0040
2.066 VV T
0.0109
6.4177
9.5364
0.0516
2.142 VB S
0.0291
9342.0957
4182.7080
75.1180
2.621 BB
0.0219
2.7495
1.8984
0.0221
4.217 BV
0.0291
1.5144
0.7982
0.0122
4.274 VB
0.0361
1.9119
0.8235
0.0154
6.818 BB
0.0515
6.8918
2.0860
0.0554
7.588 BB
0.0562
2.4055
0.6807
0.0193
12.387 BV
0.1049
1502.7212
197.1432
12.0831
12.779 VB
0.1192
409.9896
51.8626
3.2966
Sum
12436.5543
а)
Calculate the enantiomeric excess of the styrene epoxide to the nearest %.
%
b) There are some small peaks between 4 and 8 minutes. Are these more or less polar than the product styrene oxide?
2.142
12.779](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6fe1fc35-672a-49fd-831b-9642c77888ed%2F1c51fb7d-1835-44b3-8568-d2ef9028c70d%2Fkbh8s9_processed.png&w=3840&q=75)
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