a) Calculate the Bogue composition of each cement blend with the oxide composition given below. b) When you wish to remove the forms earlier, which one of the cement you could choose and why ? c) Which one has higher resistence against Sulfate, and why? d) Which one is more suitable to use in mass concreting and why?

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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1- Using below given specifications of cement blends,
a) Calculate the Bogue composition of each cement blend with the oxide
composition given below.
b) When you wish to remove the forms earlier, which one of the cement you
could choose and why ?
c) Which one has higher resistence against Sulfate, and why?
d) Which one is more suitable to use in mass concreting and why?
|Compounds:
Саб
SiO:
Cement A
(%66,6-0, 1n)
(623,7+0,1n)
%3,0
%2,8
% 1,0
% 1,0
% 1,9
3900
Cement B
(%61,0-0,1n)
(%23,0+0,1n)
%5,5
% 6,5
Cement C
(160+0,In)g
53,8g
11,lg
2,3g
2.2g
| 5,8g
8,1g
3200
A120
Fe;O
MgO
SO.
Others
Fineness (cm³/g)
%0,5
%1,0
% 2,5
2800
Bogue Formula:
C3S = 4.071Ca0-7.6024SIO2-1.4297Fe203-6.7187A1203
c2s = 8.6024SIO2+1.1Fe203+5.0683A1203-3.0710Cao
C3A = 2.6504A1203-1.6920FE203
C4AF = 3.0432Fe203
Transcribed Image Text:1- Using below given specifications of cement blends, a) Calculate the Bogue composition of each cement blend with the oxide composition given below. b) When you wish to remove the forms earlier, which one of the cement you could choose and why ? c) Which one has higher resistence against Sulfate, and why? d) Which one is more suitable to use in mass concreting and why? |Compounds: Саб SiO: Cement A (%66,6-0, 1n) (623,7+0,1n) %3,0 %2,8 % 1,0 % 1,0 % 1,9 3900 Cement B (%61,0-0,1n) (%23,0+0,1n) %5,5 % 6,5 Cement C (160+0,In)g 53,8g 11,lg 2,3g 2.2g | 5,8g 8,1g 3200 A120 Fe;O MgO SO. Others Fineness (cm³/g) %0,5 %1,0 % 2,5 2800 Bogue Formula: C3S = 4.071Ca0-7.6024SIO2-1.4297Fe203-6.7187A1203 c2s = 8.6024SIO2+1.1Fe203+5.0683A1203-3.0710Cao C3A = 2.6504A1203-1.6920FE203 C4AF = 3.0432Fe203
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