a Calculate E° for the following cell: Hg | Hg22+ || Pb4", Pb2+ | Pt You may need to use the following data: Half-cell reaction E°red (V) 2+ Hg2-"(aq) + 2e → 2Hg(/) 0.796 Pb4*(aq) + 2e → Pb2*(aq) 1.690 V b Calculate E° for the following cell: Zn | Zn2+ || Pb²* || Pb You may need to use the following data: Half-cell reaction E°red (V) 2+ Zn-"(aq) + 2e → Zn(s) -0.762 Pb-*(aq) + 2e → Pb(s) -0.127 V c Calculate E° for the following cell: Pt | Fe2", Fe3+ || MnO4 , Mn²+ | Pt You may need to use the following data: Half-cell reaction E°red (V) Fe3 (aq) + e → Fe2*(aq) MnO4 (aq) + 8H"(aq) + 5e Mn2"(aq) + 4H2O 0.769 1.512

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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a Calculate E° for the following cell:
Hg | Hg22* || Pb4*, Pb2* | Pt
You may need to use the following data:
Half-cell reaction
E°red (V)
2+
Hg2 "(aq) + 2e 2Hg(1)
0.796
Pb4(ag) + 2e → Pb2*(aq)
1.690
V
b Calculate E° for the following cell:
Zn | Zn2* || Pb2+ || Pb
You may need to use the following data:
Half-cell reaction
E°red (V)
Zn-*(aq) + 2e → Zn(s)
-0.762
Pb2*(aq) + 2e → Pb(s)
-0.127
V
c Calculate E° for the following cell:
Pt | Fe2", Fe3* || MnO4 , Mn²* | Pt
You may need to use the following data:
Half-cell reaction
E°red (V)
Fe (aq) + e → Fe2*(aq)
MnO4 (aq) + 8H"(aq) + 5e→ Mn2"(aq) + 4H20
0.769
1.512
V
Transcribed Image Text:a Calculate E° for the following cell: Hg | Hg22* || Pb4*, Pb2* | Pt You may need to use the following data: Half-cell reaction E°red (V) 2+ Hg2 "(aq) + 2e 2Hg(1) 0.796 Pb4(ag) + 2e → Pb2*(aq) 1.690 V b Calculate E° for the following cell: Zn | Zn2* || Pb2+ || Pb You may need to use the following data: Half-cell reaction E°red (V) Zn-*(aq) + 2e → Zn(s) -0.762 Pb2*(aq) + 2e → Pb(s) -0.127 V c Calculate E° for the following cell: Pt | Fe2", Fe3* || MnO4 , Mn²* | Pt You may need to use the following data: Half-cell reaction E°red (V) Fe (aq) + e → Fe2*(aq) MnO4 (aq) + 8H"(aq) + 5e→ Mn2"(aq) + 4H20 0.769 1.512 V
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