A bullet shot underwater will experience "viscous drag" and follow this velocity equation:vx(t) = vie−btwhere vi = 232 m/s and b = 0.25 s-1. The bullet has an initial position xi = 58.1 m at ti = 0 s.What is the location of the bullet at time t = 0.7 seconds? What is the maximum position of the bullet (if you wait a long time, what will its position be)? What is the x component of the acceleration of the bullet 0.5 seconds after the bullet is fired?

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Projectile Motion