A bullet shot underwater will experience "viscous drag" and follow this velocity equation:vx(t) = vie−btwhere vi = 232 m/s and b = 0.25 s-1. The bullet has an initial position xi = 58.1 m at ti = 0 s.What is the location of the bullet at time t = 0.7 seconds? What is the maximum position of the bullet (if you wait a long time, what will its position be)? What is the x component of the acceleration of the bullet 0.5 seconds after the bullet is fired?

The magnitude of a particle's velocity is observed to vary with time according to the equation: |v = Bt where Bis a positive constant. What are the units of B? т S m Om: s? O m· .3 m

PLEASE ANSWER QUICKLT AND WILL RATE HIGHLY *15

A particle moves along the x-axis with position function x(t) = At² + B²²³, where 4 = 3 m s-² and B=ms-3 are constants. Find the instantaneous velocity vx and the instantaneous acceleration ax of the particle at time t = 2 s. Give your answers by entering the appropriate integer numbers in the two empty boxes below (you don't need to concern yourself with significant figures in this question). At time t=2s : Vx = At time t=2s : ax = ms-1. ms-2. You may use the following standard derivative: dc4" dt nCtn - 1 where C and are any constants. n