Answered: A bowling ball of mass 7 kg is dropped…

Classical Dynamics of Particles and Systems

5th Edition

ISBN:9780534408961

Author:Stephen T. Thornton, Jerry B. Marion

Publisher:Stephen T. Thornton, Jerry B. Marion

Chapter9: Dynamics Of A System Of Particles

Section: Chapter Questions

Problem 9.60P

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Question

A bowling ball of mass 7 kg is dropped from the top of a tall building. It safely lands on the ground 8.0 seconds later. Neglecting air friction, the height of the building is?

Expert Solution

Step 1

Given: The mass of the ball is 7 kg.

The time is 8.0 s.

To determine: The height of the building.

The first equation of motion is

$v = u + a t$

where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Here, a is equal to g, acceleration due to gravity

$v = u + g t$

The ball is dropped from the top of a tall building, so the initial velocity is zero.

Substitute 0 for u, $9.8 m / s^{2}$ for g and 8.0 s for t in the above equation to calculate the final velocity.

$\begin{array}{rcl} v & = & 0 + 9.8 m / s^{2} \times 8.0 s \\ = & 78.4 m / s \end{array}$

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