A Boolean expression is given as follow: F = (A+ B)C+ D)B (i) Draw a logic gate circuit to represent the given Boolean expression. (ii) Simplify the given Boolean expression. (iii) Find the value of F if ALL inputs are equal to 1.
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Draw a logic gate to represent the given boolean expression
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- Figure (a) shows a combinational logic circuit. It is simulated with a sequence of inputs shown in Figure (b). F(A B.C) Figure (a) B F (A, B, C) Figure (b) a. Determine the output expression for F with the input variables A B and C. Simplify the function using Boolean Algebra technique. b. Sketch the simplified circuit for F. c. Draw the truth table for the function F(A,B,C). d. Determine the timing diagram for the function F(A,B,C) based on the timing diagram given in Figure (b).Draw the logic circuits for the following Boolean expressions and simplify the logic expressions using theorems of Boolean algebra. (Ā+B)(A+ Ē + D)DUsing the Boolean rules, delermine the outputs of the logic circuits below: a) A b). c) c). B d) A
- Draw the equivalent logic circuit diagram of the following expressions : a. XY = F b. X + Y = F XÝZ = F c. d. XY + XZ = F e. XYZ + XÝZ = F2.1 Combinational logic circuits. Tabulates a truth table for the following Boolean expression shown in Equation 1.1. f = A.B.C + A.B.C + A.B.C (1.1) 2.2 Half adder. A half adder is a circuit that adds two binary digits, A and B. It has two outputs, sum (S) and carry (C). The carry signal represents an overflow into the next digit of a multi-digit addition. Figure 1.2 depicted a logic diagram for a half adder. a. derives the Boolean expression for s and c. b. tabulates a truth table for the half adder. Ao Bo Figure 1.2: Half adder os S CA Write the Boolean expression of the following Logic diagram. B C D=
- Consider the given logic equation below. Draw the logic diagram then simplify it using Boolean Algebra. Draw the logic diagram based on the simplified logic equation. X = A'BC' + A'B'C' + AB'C + AB'C' + A'B'C From the given logic diagram, trace the output using all possible input combination. Give it a conclusion upon completion..Using Boolean theorems, simplify the output expression for the circuit in the figure. Show all the steps used to simplify the expression.Design the following combinational logic circuit with a four-bit input and a three-bit output. The input represents two unsigned 2-bit numbers: A1 A0 and B1 B0. The output C2 C1.C0 is the result of the integer binary division A1 A0/B1 B0 rounded down to three bits. The 3-bit output has a 2-bit unsigned whole part C2 C1 and a fraction part CO. The weight of the fraction bit CO is 21. Note the quotient should be rounded down, i.e. the division 01/11 should give the outputs 00.0 (1/3 rounded down to 0) not 00.1 (1/3 rounded up to 0.5). A result of infinity should be represented as 11.1. A minimal logic implementation is not required. (Hint: start by producing a truth table of your design).
- Task 6: Simplifying Boolean functions in EWB using the logic converter Simplify the following Boolean expression in EWB using the logic converter F (A, B, C) = AB'C'+ A'B'C'+ A'BC'+ A'B'C(B)- Show the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A.B+C+ (C+ B).D 2) Y= A.B.C+B. D. (A OB)+C 3) Y= A.B (C+ D) +D+ A OBShow the Ladder logic program and the equivalent Function Block Diagram for the following Boolean expressions without any simplification: - 1) Y= A.B+C+(C+B). D 2) Y= A.B.C+B.D. (AOP)+C 3) Y= A.B (C + D) + D+ A B