A block of mass me is at the top (h from the bottom) of a movable wedge with angle and mass mw. There is no friction between the block and wedge or between the wedge and the floor. Since the wedge can move, as the block slides down the wedge, it pushes the wedge backwards. m VW VB

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Please give me the answers to all parts. Show your work.

**Scenario Description:**

A block of mass \( m_B \) is at the top (height \( h \) from the bottom) of a movable wedge with angle \( \theta \) and mass \( m_W \). There is no friction between the block and the wedge or between the wedge and the floor. As the block slides down the wedge, it pushes the wedge backwards.

**Illustration Explanation:**

The diagram consists of an initial and final scenario:
- **Initial:** The block \( m_B \) is positioned at the top of the wedge of mass \( m_W \), with height \( h \) indicated.
- **Final:** After sliding, the block \( m_B \) moves to the right with velocity \( v_B \) and the wedge \( m_W \) moves to the left with velocity \( v_W \).

**Questions:**

(a) Write down the energy conservation equation for this scenario.

(b) Write down the momentum conservation equation for this scenario.

(c) Find the final speed of the wedge, once the block has slid all the way down the ramp.

(d) Find the final speed of the block.

(e) Test your answers to parts (a) and (b) by taking the limits as \( m_W \rightarrow \infty \).
Transcribed Image Text:**Scenario Description:** A block of mass \( m_B \) is at the top (height \( h \) from the bottom) of a movable wedge with angle \( \theta \) and mass \( m_W \). There is no friction between the block and the wedge or between the wedge and the floor. As the block slides down the wedge, it pushes the wedge backwards. **Illustration Explanation:** The diagram consists of an initial and final scenario: - **Initial:** The block \( m_B \) is positioned at the top of the wedge of mass \( m_W \), with height \( h \) indicated. - **Final:** After sliding, the block \( m_B \) moves to the right with velocity \( v_B \) and the wedge \( m_W \) moves to the left with velocity \( v_W \). **Questions:** (a) Write down the energy conservation equation for this scenario. (b) Write down the momentum conservation equation for this scenario. (c) Find the final speed of the wedge, once the block has slid all the way down the ramp. (d) Find the final speed of the block. (e) Test your answers to parts (a) and (b) by taking the limits as \( m_W \rightarrow \infty \).
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