A block of mass m = 0.65 kg, moving at constant speed v = 5.00 m/s, slides along a horizontal, frictionless surface and collides with and sticks to the end of an initially vertical, stationary thin rod, of mass M = 5.00 kg, and length L = 0.50O m. See the figure below. The other end of the rod is attached to a horizontal frictionless pivot which allows the mass-rod system to rotate to an angle 0 with the vertical direction. What is the maximum angle 0max the rod makes with the vertical? (The moment of inertia of a uniform thin rod about an axis through one end is given by ML2/3) L

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Chapter1: Units, Trigonometry. And Vectors
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A block of mass m =
constant speed v = 5.00 m/s, slides along a
horizontal, frictionless surface and collides with
and sticks to the end of an initially vertical,
stationary thin rod, of mass M= 5.00 kg, and
length L = 0.500 m. See the figure below. The
0.65 kg, moving at
other end of the rod is attached to a horizontal
frictionless pivot which allows the mass-rod
system to rotate to an angle 0 with the vertical
direction. What is the maximum angle Omax the
rod makes with the vertical? (The moment of
inertia of a uniform thin rod about an axis
through one end is given by ML2/3)
L
Transcribed Image Text:A block of mass m = constant speed v = 5.00 m/s, slides along a horizontal, frictionless surface and collides with and sticks to the end of an initially vertical, stationary thin rod, of mass M= 5.00 kg, and length L = 0.500 m. See the figure below. The 0.65 kg, moving at other end of the rod is attached to a horizontal frictionless pivot which allows the mass-rod system to rotate to an angle 0 with the vertical direction. What is the maximum angle Omax the rod makes with the vertical? (The moment of inertia of a uniform thin rod about an axis through one end is given by ML2/3) L
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