College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- In the figure, a 7.90 g bullet is fired into a 0.430 kg block attached to the end of a 0.140 m nonuniform rod of mass 0.578 kg. The block-rod-bullet system then rotates in the plane of the figure, about a fixed axis at A. The rotational inertia of the rod alone about A is 0.0761 kg·m2. Treat the block as a particle. (a) What then is the rotational inertia of the block-rod-bullet system about point A? (b) If the angular speed of the system about A just after impact is 3.64 rad/s, what is the bullet's speed just before impact?arrow_forwardA perfectly elastic ball bounces against a surface with a velocity vo = 2.4 m/s at an angle 0o = 45 degrees to the vertical. As a result of the impact, the ball bounces upward at an angle 0₁ = 23.2 degrees but also gains a topspin w₁ = 152 rad/s due to the rough surface. The ball has mass m = 10 grams and radius R = 16 mm. The moment of inertia of a solid sphere is /G = (2 m R²) / 5. The coefficient of restitution for the impact e = 1, so that energy can be assumed to be conserved during impact. g W₁ = 0 Vo 0₁ W₁ Calculate the magnitude of the velocity v₁ of the ball after impact. Ov=2.85 m/s O V = 2.4 m/s O V = 1.84 m/s O V = 1.67 m/s V₁arrow_forwardTwo identical alleles are moving on horizontal surfaces. The center of masses of each has the same linear speed. However, one wheel is rolling while the other is sliding on a frictionless Surface without rolling. Each wheel then encounters as an inclined plane. One continues to roll up the incline, while the other continues to slide up. Eventually wheel is a disk of mass 2.72kg . On the horizontal surfaces the center of each wheel moves a linear speed of 6.56m/s. (A), (b) what is the total kinetic energy of wheel? (C) (D) determine the maximum height reached by each will as it moves up the incline.arrow_forward
- A block of mass m = 0.75 kg, moving at constant speed v = 4.00 m/s, slides along a horizontal, frictionless surface and collides with and sticks to the end of an initially vertical, stationary thin rod, of mass M = 5.50 kg, and length L = 0.750 m. See the figure below. The other end of the rod is attached to a horizontal frictionless pivot which allows the mass-rod system to rotate to an angle θ with the vertical direction. What is the maximum angle θmax the rod makes with the vertical? (The moment of inertia of a uniform thin rod about an axis through one end is given by ML2/3)arrow_forwardThe figure shows a small particle of mass 0.278 kg that is moving with a speed of 7.29 m/s when it collides and sticks the the edge of a uniform solid cylinder. The cylinder is free to rotate about an axis through its center. The cylinder has a mass of 2.677 kg, and a radius of 0.28 m, and is initially at rest. What is the angular velocity of the system after the collision? Express your answer in radians/s to 3 significant figures. Before Afterarrow_forwardA uniform solid disk of mass m = 2.99 kg and radius r = 0.200 m rotates about a fixed axis perpendicular to its face with angular frequency 6.05 rad/s. (a) Calculate the magnitude of the angular momentum of the disk when the axis of rotation passes through its center of mass. kg • m2/s (b) What is the magnitude of the angular momentum when the axis of rotation passes through a point midway between the center and the rim? kg • m2/sarrow_forward
- A thin rod of length 2.95 m and mass 13.3 kg is rotated at an angular speed of 3.95 rad/s around an axis perpendicular to the rod and through its center of mass. Find the magnitude of the rod's angular momentum. kg •m?/sarrow_forwardA playground merry-go-round has a radius of R = 4.0 m and has a moment of inertia Icm = 7.0 x 10³ kgm² about an axis passing through the center of mass. There is negligible friction about its vertical axis. Two children each of mass m = 25 kg are standing on opposite sides a distance ro = 3.0 m from the central axis. The merry-go-round is initially at rest. A person on the ground applies a constant tangential force of F= 2.5 x10² N at the rim of the merry-go-round for a time At =1.0 x 10¹ s. اناما R a. What is the magnitude of angular acceleration of the merry-go-round? b. What is the angular speed of the merry-go-round when the person stopped applying the force? c. What is the rotational kinetic energy of the merry-go-round when the person stopped applying the force? d. The two children then walk inward and stop a distance of r1 =1.0 m from the central axis of the merry-go-round. What is the angular velocity of the merry-go- round when the children reach their final position? What is…arrow_forward
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