A batch reactor is charged with 11.1 kmol of sulfur dioxide and 6.3 kmol oxygen, which react reversibly to form sulfur trioxide. The equilibrium constant for this reaction at the pressure and temperature of the reactor is provided below. a) Which reactant is limiting? SO₂ + 1/2 O₂ → SO3 yso3 yso₂ (VO₂) ¹/2 K= = 10.5 b) What is the maximum percent conversion of the limiting reactant (i.e., the percent conversion at equilibrium)? c) Calculate the mole fraction of each species at equilibrium.
A batch reactor is charged with 11.1 kmol of sulfur dioxide and 6.3 kmol oxygen, which react reversibly to form sulfur trioxide. The equilibrium constant for this reaction at the pressure and temperature of the reactor is provided below. a) Which reactant is limiting? SO₂ + 1/2 O₂ → SO3 yso3 yso₂ (VO₂) ¹/2 K= = 10.5 b) What is the maximum percent conversion of the limiting reactant (i.e., the percent conversion at equilibrium)? c) Calculate the mole fraction of each species at equilibrium.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:3. A batch reactor is charged with 11.1 kmol of sulfur dioxide and 6.3 kmol oxygen, which react reversibly
to form sulfur trioxide. The equilibrium constant for this reaction at the pressure and temperature of the
reactor is provided below.
a) Which reactant is limiting?
SO₂ + 1/2 O₂ → SO3
yso3
yso₂ (VO₂) ¹/2
K=
= 10.5
b) What is the maximum percent conversion of the limiting reactant (i.e., the percent conversion at
equilibrium)?
c) Calculate the mole fraction of each species at equilibrium.
d) What is the maximum percent conversion of sulfur dioxide that can be attained by increasing the
amount of oxygen fed to the reactor?
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